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evablogger [386]
3 years ago
5

Keeping things in perspective and expressing your feelings are defense mechanisms. true or false​

Physics
1 answer:
Katen [24]3 years ago
6 0

Answer:

Defense Mechanism is the psychological strategy to manipulate or distort the reality to reduce anxiety and maintain self-schema.

Answer: False

Explanation:

The Defense Mechanism of Psychology:

A smart psychological strategy used to manipulate, defy or distort the reality in order to escape from anxiety and maintain self-schema.

The concept is to shield the mental state from being emotionally hurt or depressed by an unwanted or unpleasant situation. This mechanism helps people in recovering from psychological or mental illness.

There are various types of defense mechanism such as regression, repression, denial, compensation etc. which individuals use to escape from the real state. Hence, keeping things in perspective and expressing your feelings are definitely not the acts which fall under the Defense mechanism.

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Independent variable - Water depth

The independent variable is something that is purposely changed in order to see the effects of change on the dependent variable. So since Carl wants to measure the temperature of water at different depths we will purposely change the depth of the water in order to observe how this would affect the temperature. 

Dependent variable - Temperature of the water 

The dependent variable is something that is dependent on the independent variable and is assumed to change as the independent variable changes. So we can determine that the temperature of the water is the independent variable as Carl expects it to change with the depth of the water. Another reason we can determine this is the dependent variable is because Carl can change the depth of the water measured but not the temperature of the water depths. 
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<h3>What is the fullform of SMPS ?​</h3>

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In an experiment, a variable, position-dependent force F(x)F(x) is exerted on a block of mass 1.0kg1.0kg that is moving on a hor
leonid [27]

Answer:

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

Explanation:

Given that,

Mass of block = 1.0 kg

Dependent force = F(x)

Frictional force = F(f)

Suppose, the following information would students need to test the hypothesis,

(A) The function F(x) for 0 < x < 5 and the value of F(f).

(B) The function a(t) for the time interval of travel and the value of F(f).

(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).

(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).

We know that,

The work done by a force is given by,

W=\int_{x_{0}}^{x_{f}}{F(x)\ dx}.....(I)

Where, F(x) = net force

We know, the net force is the sum of forces.

So, \sum{F}=ma

According to question,

We have two forces F(x) and F(f)

So, the sum of these forces are

F(x)+(-F(f))=ma

Here, frictional force is negative because F(f) acts against the F(x)

Now put the value in equation (I)

W=\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}

We need to find the value of \int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}

Using newton's second law

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{ma\ dx}...(II)

We know that,

Acceleration is rate of change of velocity.

a=\dfrac{dv}{dt}

Put the value of a in equation (II)

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{m\dfrac{dv}{dt}dx}

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{v_{0}}^{v_{f}}{mv\ dv}

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}

Now, the work done by the net force on the block is,

W=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}

The work done by the net force on the block is equal to the change in kinetic energy of the block.

Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

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