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2 years ago

Ayudaaaaa por favorrrrrrrr!

Physics

1 answer:

abruzzese [7]2 years ago

6 0

Same for #1 I have to say the same thing

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You sit at the middle of a large turntable at an amusement park as it is set spinning on nearly frictionless bearings, and then

jolli1 [7]

Answer:

Decrease

Explanation:

If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :

"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."

3 0

2 years ago

Name two objects that use electric motors and are commonly found in houses.

DiKsa [7]

Refrigerator - Contains Induction motor in compressor.
Toys - DC motors.

4 0

2 years ago

Read 2 more answers

You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont

Scilla [17]

Answer:

$R_{max} = 51.84 m$

Explanation:

When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as

$t = 4.6 s$

here we can say

$\Delta y = 0 = v_i t + \frac{1}{2}at^2$

$0 = v_i t - \frac{1}{2}(9.8)t^2$

put t = 4.6 s then we have

$v_i = 22.54 s$

Now in order to find the maximum range we can say

$R = \frac{v^2 sin2\theta}{g}$

so in order to have maximum range we can say

$\theta = 45 degree$

$R_{max} = \frac{v^2}{g}$

$R_{max} = \frac{22.54^2}{9.8}$

$R_{max} = 51.84 m$

5 0

2 years ago

3 نقطة (نقاط)

Molodets [167]

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

$W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J$

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force P. Let $W_P$ be the work done by the force P. Then the total work done on the block is

$W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}$

5 0

2 years ago

How far would a spacecraft moving in a circular orbit 500 km above Pluto's surface travel during that time?

Ilia_Sergeevich [38]

Answer:

The speed of the spacecraft should be 719.35m/s

Explanation:

if the spacecraft is orbiting the planet with a circular orbit, the gravitational force must act as a centripetal force. This means:

$F_G=F_c\\\frac{GmM}{d^2}=m\frac{v^2}{d}$

In this case, the pluto's mass M is 1.3099·10^22 kg. The radius of the planet R is 1188.3Km and G is the gravitational constant. Therefore:

$\displaystyle\frac{G M}{d^2}=\frac{v^2}{d}\\v=\sqrt{\frac{GM}{d} } =\sqrt{\frac{GM}{(R + 500km)} } =719.35m/s$

7 0

2 years ago