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Alenkasestr [34]
3 years ago
9

Anyone plz help!! I need the answer of q-b !

Physics
1 answer:
Lady_Fox [76]3 years ago
6 0
The coil is rotated rapidly in the magnetic field.
The magnetic flux linked with the coil changes and thus, an emf is induced which leads to the flow of current .

when the coil rotates and is in a position along the direction of the magnetic field, emf is maximum while when it is perpendicular to the magnetic field,emf is 0.

Thus an ac generator converts mechanical to electrical energy.It works on the principle of electromagnetic induction. The polarity at the supply terminals changes like.. 100 times a second if the frequency is 50 Hz(50 times+ and 50 times - )

hope it helps!
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Which data set has the largest standard deviation
AfilCa [17]

Answer:

<em>The data set marked as B has the largest standard deviation</em>

Explanation:

<u>Standard Deviation</u>

It's a number used to show how a set of measurements is spread out from the average value. A low standard deviation means that most of the values are close to the average. A high standard deviation means that the numbers are more spread out.

The formula for the standard deviation is

\displaystyle \sigma=\sqrt{\frac{\sum (x_i-\mu)^2}{n}}

Where x_i is the value of each measurement, n is the number of elements in the set, and \mu is the average or media of the values, defined as

\displaystyle \mu=\frac{\sum x_i}{n}

Let's analyze each set of data:

A.3,4,3,4,3,4,3

The average is

\displaystyle \mu=\frac{3+4+3+4+3+4+3}{7}=3.43

Computing the stardard deviation:

\sigma=\sqrt{\frac{(3-3.43)^2+(4-3.43)^2+(3-3.43)^2+(4-3.43)^2+(3-3.43)^2+(4-3.43)^2+(3-3.43)^2}{7}}

\sigma=0.5

B.1,6,3,15,4,12,8

The average is

\displaystyle \mu=\frac{1+6+3+15+4+12+8}{7}=7

Computing the stardard deviation:

\sigma=\sqrt{\frac{(1-7)^2+(6-7)^2+(3-7)^2+(15-7)^2+(4-7)^2+(12-7)^2+(8-7)^2}{7}}

\sigma=4.7

C. 20, 21,23,19,19,20,20

The average is

\displaystyle \mu=\frac{20+21+23+19+19+20+20}{7}=20.29

Computing the stardard deviation:

\sigma=\sqrt{\frac{(20-20.29)^2+(21-20.29)^2+(23-20.29)^2+(19-20.29)^2+(19-20.29)^2+(20-20.29)^2+(20-20.29)^2}{7}}

\sigma=1.3

D.12,14,13,14,12,13,12

The average is

\displaystyle \mu=\frac{12+14+13+14+12+13+12}{7}=12.86

Computing the stardard deviation:

\sigma=\sqrt{\frac{(12-12.86)^2+(14-12.86)^2+(13-12.86)^2+(14-12.86)^2+(12-12.86)^2+(13-12.86)^2+(12-12.86)^2}{7}}

\sigma=0.8

We can see the data set marked as B has the largest standard deviation

5 0
3 years ago
Why does a solid keep its shape
garri49 [273]

Answer:

Solids can hold their shape because their molecules are tightly packed together. Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms.

7 0
3 years ago
Does organisms get rid of waste
Strike441 [17]
Bacteria get rid of waste through their semi-permeable membrane by diffusion. The waste is pushed out of the organism in the form of liquid or gas. The waste released by bacteria is usually toxic and is what makes people sick.
3 0
3 years ago
Read 2 more answers
Any projectile always has a constant vertical acceleration of _______.
Mashcka [7]

Answer:

The answer to your question is: C. -9.81 m/s²

Explanation:

A. 9.81 m/s²  acceleration is considered positive when it goes to the center of the earth, so this option is incorrect.

B. 0 m/s²  This option is incorrect because acceleration is 0 for a linear motion without acceleration.

C. -9.81 m/s²  If a projectile goes to the sky, then the acceleration will be negative.

D. It is not constant. Acceleration is constant.

8 0
3 years ago
A block of mass m=1kg sliding along a rough horizontal surface is traveling at a speed v0=2m/s when it strikes a massless spring
topjm [15]

Here we can use the work energy theorem

W_f + W_s = K_f - K_i

here we know that

K_f = 0

as it come to rest finally

K_i = \frac{1}{2}mv_i^2

K_i = \frac{1}{2}\times 1\times 2^2

K_i = 2 J

now work done by friction force will be given as

W_f = - F_f \times d = -\mu mg d

W_f = - \mu(1)(9.8)(0.10) = - 0.98\mu

Work done by spring force is given as

W_s = \frac{1}{2}k(x_i^2 - x_f^2)

W_s = \frac{1}{2}(10)( 0 - 0.10^2)

W_s = -0.05 J

so now plug in all data above

- 0.05 - \mu(0.98) = 0 - 2

\mu = 1.99

so above is the friction coefficient


4 0
3 years ago
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