Rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122M.
A rate law indicates the rate of a chemical response depends on reactant concentration. For a response inclusive of the price regulation commonly has the form rate = ok[A]ⁿ, in which okay is a proportionality constant known as the fee regular and n is the order.
The charge of a chemical response is, perhaps, its maximum crucial asset because it dictates whether or not a reaction can arise all throughout an entire life. knowing the charge regulation, an expression concerning the price to the concentrations of reactants can assist a chemist to modify the response conditions to get an extra suitable rate.
half-life is the time taken for the radioactivity of a substance to fall to 1/2 its authentic cost whereas implies existence is the common life of all the nuclei of a particular risky atomic species.
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Answer:
0.744 mol
Explanation:
the balanced equation for the reaction is
8Fe + S₈ ---> 8FeS
molar ratio of Fe to S₈ is 8:1
number of moles of Fe - 55.0 g / 56 g/mol = 0.98 mol
number of moles of S - 23.8 g / 256 g/mol = 0.093 mol
if we are to assume that S₈ is the limiting reactant
if 1 mol of S₈ reacts with 8 mol of Fe
then 0.093 mol of S₈ reacts with - 8 x 0.093 mol = 0.744 mol of Fe
however there's 0.98 mol of Fe present but only 0.744 mol of Fe is needed
therefore Fe is in excess and S₈ is the limiting reagent
molar ratio of S₈ to FeS is 1:8
then 0.093 mol of S₈ reacts with - 8 x 0.093 = 0.744 mol of FeS
number of FeS moles produced is 0.744 mol
Molarity = mol/L
(0.5M) = (2mol)/L
(2mol)/(0.5M) = L
4 liters
Answer:
D. MgO
Explanation:
We need to look at the charge of element. (Look at a periodic table for this)
Mg, which is Magnesium, has a charge of 2+ because it's in the second column, or group, from the left.
O, which is Oxygen, has a charge of 2- because it's in the second column, or group, from the right.
Since Mg is 2+, it's the cation and since O is 2-, it's the anion. We can put these two elements together into an ionic compound.
Mg^(2+) and O^(2-) becomes Mg2O2, where we can cancel the 2s: MgO.
Thus, the answer is D.
Hope this helps!
