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ladessa [460]
3 years ago
9

the mass of sample X is 20.0g. it was placed in a graduated cylinder and the water level rose from A to B. what is the density o

f sample X? pay close attention to significant figures
Chemistry
1 answer:
Andreyy893 years ago
6 0

Answer:

4

Explanation:

D=M/V

D=20.0/5

D=4

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In normal conditions, warm water "piles up" in the Western Pacific Ocean.<br><br> True<br> False
kakasveta [241]
In normal conditions, warm water does "pile up" in the" Western Pacific Ocean.
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3 years ago
A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0
3 years ago
Wine is 13 % alcohol by volume. How many milliliters of alcohol are in a 0.900-L bottle of wine?
AURORKA [14]
13% of 0.900 is 0.117
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3 0
2 years ago
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fomenos

Answer:

D = 5.3 g/mL

Explanation:

Density = Mass over Volume

D = m/V

Step 1: Define

D = unknown

m = 16 g

v = 3.0 mL

Step 2: Substitute and Evaluate

D = 16 g / 3.0 mL

D = 5.333333333 g/mL

Step 3: Simplify

We have 2 sig figs.

5.333333333 g/mL ≈ 5.3 g/mL

6 0
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What are the properties of a bandaid
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