Answer:
FCW in car stands for <em>Forward Collision Warning.
</em>
<u>Explanation:</u>
The vehicle speed is monitored by <em>FCW system</em>, this is an advanced technology which indicates to the rear vehicle that a crash is going to happen if the vehicle gets close <em>because of speed</em>. This FCW systems monitor’s distance between the vehicles and speed of the vehicles.
<em>FCW system do not control the vehicle completely</em>. This system consists of sensors to detect stationary or slower-moving vehicles. A signal alerts the driver if the <em>distance between the vehicles is less</em> so that crash is being happened. It helps driver from crash by changing his route. Cars with this technology consists of audible alert.
The question is not complete. We are supposed to find the average value of v_o.
Answer:
v_o,avg = 0.441V
Explanation:
Let t1 and t2 be the start and stop times of the output waveforms. Thus, from the diagram i attached, using similar triangles, we have;
3/(T/4) = 0.7/t1
So, 12/T = 0.7/t1
So, t1 = 0.7T/12
t1 = 0.0583 T
Also, from symmetry of triangles,
t2 = T/2 - t1
So, t2 = T/2 - 0.0583 T
t2 = 0.4417T
Average of voltage output is;
v_o,avg = (1/T) x Area under small triangle
v_o,avg = (1/T) x (3 - 0.7) x (T/4 - t1)
v_o,avg = (1/T) x (2.3) x (T/4 - 0.0583 T)
v_o,avg = (1/T) x 2.3 x 0.1917T
T will cancel out to give;
v_o,avg = 0.441V
Answer:
Correct sentence: (c) more.
Explanation:
Otto cycle:
An ideal Otto cycle models the behavior of an explosion engine. This cycle consists of six steps, as indicated in the figure. Prove that the performance of this cycle is given by the expression
η = 1 - (1/r^(ρ-1))
where r = VA / VB is the compression ratio equal to the ratio between the volume at the beginning of the compression cycle and at the end of it. ρ=1.4
Diesel cycle:
The ideal Diesel cycle is distinguished from the ideal Otto in the combustion phase, which in the Otto cycle is assumed at a constant volume and in the Diesel at constant pressure. Therefore the performance is different.
If we write the performance of a Diesel cycle in the form
:
η = 1 - (1/r^(ρ-1)) × ( (r^ρ)-1)/(ρ^(r-1)) )
we see that the efficiency of a Diesel cycle differs from that of an Otto cycle by the factor in parentheses. This factor is always greater than the unit, therefore, for the same compression reasons r
diesel performance is less than otto performance
\ eta_ \ mathrm {Diesel} <\ eta_ \ mathrm {Otto} \,
Answer:
Explanation: Peak – the highest point above the rest position. Trough – the lowest point below the rest position. Amplitude – the maximum displacement of a point of a wave from its rest position. Wavelength – distance covered by a full cycle of the wave. Usually measured from peak to peak, or trough to trough.
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