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Viktor [21]
3 years ago
9

Tollens’ test, also known as silver-mirror test, is a qualitative laboratory test used to distinguish between an aldehyde and a

ketone. It exploits the fact that aldehydes are readily oxidized (see oxidation),
whereas ketones are not.
Tollens’ test uses a reagent known as Tollens’ reagent,
which is a colorless,
basic,
aqueous solution containing silver ions coordinated to ammonia [Ag(NH3)2+].
It is prepared using a two-step procedure.
Chemistry
1 answer:
Makovka662 [10]3 years ago
3 0

Explanation:

Tollens' reagent is prepared by using two-step process : -

Step 1:

Silver oxide is formed by mixing aqueous silver nitrate with base like sodium hydroxide. The reaction is shown below as:

AgNO_3 + NaOH &\rightarrow AgOH + NHO_3 \nonumber \\ 2AgOH &\rightarrow Ag_2O + H_2O

Step 2

Ammonia solution is drop-wise added until all the silver oxide dissolves to form the reagent. The reaction is shown below as:

Ag_2O + 4NH_3 + H_2O \rightarrow 2Ag(NH_3)_2^+ + 2OH^-

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HELP PLS !!!! :))Formula unit of Sr and CI<br><br> Formula unit of AI and S
xenn [34]

Answer : The formula unit of Sr & Cl is SrCl_2 and the formula unit of Al & S is Al_2S_3

Explanation :

Formula unit : it is defined as the lowest number ratio of ions of an elements in an ionic compound or covalent compound.

For the formula unit of Sr & Cl, two chloride ions(Cl^-) are needed to neutralize the one strontium ion(Sr^{2+}).

For the formula unit of Al & S, three sulfide ions(S^{2-}) are needed to neutralize the two aluminium ion(Al^{3+}).

The formula unit of SrCl_2 and Al_2S_3 are shown below.

4 0
3 years ago
What is a magnetic field what does it do??
NikAS [45]

Answer:

attract things or hold them in place

Explanation:

a magnetic field is similar to gravity. Like gravity a magnetic field can hold or pull things.

5 0
3 years ago
Read 2 more answers
4. Two double stranded fragments of DNA are exactly the same length. At 89 C, fragment A has completely denatured, which means t
nignag [31]

Answer:

The correct answer is "Fragment B likely has a higher Guanosine/Citosine content".

Explanation:

Guanosine/Citosine content, or GC content, refers to how many molecules of guanosine and citosine have a DNA fragment, respect to the content of adenine and thymine. The higher the GC content, the higher the temperature needed to denature the fragment of DNA. This happens because guanosine and citosine establish three hydrogen bonds, while adenine and thymine establish two hydrogen bonds when they bind together. Therefore, if fragment A and B are the same length, but at 89 C only fragment A is completely denatured, fragment B likely has a higher GC content.

4 0
3 years ago
Please help, and I’ll thank you.
coldgirl [10]

Answer:

There will be formed 13.82 grams of Fe3O4.

Explanation:

<u>Step 1:</u> the balanced reaction

3 Fe(s) + 4 H2O(l) —— Fe3O4(s) + 4 H2(g)

We see that for 3 moles Fe consumed, there will be consumed 4 moles of H20 and produced 1 mole of Fe3O4 and 4 moles of H2.

<u>Step 2:</u> Calculating moles

⇒mole = mass / Molar mass

⇒moles Fe = 10g / 55.845g/mole = 0.179 moles

⇒moles H2O = 10g / 18g/mole = 0.5556 moles

Since we have 4 moles of H2O consumed for 3 moles of Fe, this means that for 0.179 moles of Fe, we have :

0.179 / 4 *3 = 0.2387 moles of H2O consumed

This means that Fe will be completely consumed and there will remain 0.2387 moles of H2O.

Fe is the limiting reactant and H2O is in excess.

<u>Step 3: </u>Calculate moles of Fe3O4

For 3 moles of Fe consumed, we have 1 mole of Fe3O4 produced.

This means, that for 0.179 moles of Fe consumed, we have 0.179/3 =0.05967 molesof Fe3O4 produced.

<u>Step 4:</u> Calculating mass of Fe3O4

mass= number of moles * Molar mass

mass Fe3O4 = 0.05967 mole * 231.55g/mole = 13.8166 g ≈ 13.82grams of Fe3O4

There will be formed 13.82 grams of Fe3O4.

5 0
3 years ago
Two trials are run, using excess water. In the first trial, 7.8 g of Na2O2(s) (molar mass 78 g/mol) is mixed with 3.2 g of S(s).
Tema [17]

Answer:

The answer is "Option C".

Explanation:

Given equation:

2Na_20_2 (s)+S(s)+2H_2O \longrightarrow  4NaOH(aq)+SO_2(aq)

\to \Delta H^{\circ}_{rxn} (298\ K) = -610 \frac{kJ}{mol}

\to Na_2O_2  \ Mass = 7.8 \ g\\\\ \to  Na_2O_2 \ Molar \ mass = 78 \frac{g}{mol}

Na_2O_2 Has been the reactant which is limited since the two experiments are equal toNa_2O_2 for relationship between stress amounts.

Na_2O_2, n =\frac{Mass of Na_2O_2}{Molar mass of Na_2 O_2}=\frac{7.8 \ g}{78 \frac{g}{mol}} =0.1 \ mol \\\\q=\Delta H^{\circ}_{rxn} \times n = \frac{ -610 \ kJ}{ 2 \ mol \ Na_2 O_2} \times 0.1 \ mol  \ Na_2O_2= 30.5 \ KJ\\\\

Limiting reactant =Na_2O_2

q=30.5 \ kJ \approx 30 \ kJ

8 0
3 years ago
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