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Andre45 [30]
3 years ago
13

La unidad de calor es la caloría; es posible expresarla en el sistema internacional de medidas??

Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Yes, the calorie can be expressed in SI units

Explanation:

1 calorie (1 cal) is defined as the amount of heat energy that must be supplied to 1 gram of water in order to raise its temperature by 1 degree Celsius (1^{\circ}C.

The calorie is not a unit of the International System (SI): the SI unit for the energy is the Joule (J).

However, it is possible to convert energy from calories to Joules, and viceversa. In fact, the conversion factor between the two units is:

1 calorie = 4.184 Joules

So, to convert from calories to Joules we simply multiply by 4.184, while if we want to convert from Joules to calories, we just divide by 4.184.

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There is a displacement. Just because the ball is thrown up, and not crossways, doesn't mean its location is not moving. Remember, positive displacement is together a displacement in the direction east, right, and up.  The velocity is the distance over time. To compute that, you must look how high the ball moved before falling back down. Acceleration is expected to be constant at 9.80m/s^2. That is the force of gravity. But remember that you are disregarding air friction when you are computing the acceleration.

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The loss of static electricity as electric charges transfer from one object to another is called
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How much heat is gained by 1.0 gram of iron when its heated 15 degrees celsius
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All of the noble gases, Group 18, have eight valence electrons in its outer shell (excluding helium which only has two). Which o
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Zero or +2

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It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass
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Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

v^{2}=u^{2}+2\cdot a \cdot s

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/Sec^{2}

s= Distance traveled before stop m

Case 1

u=  13 m/sec, v=0, s= 57.46 m, a=?

0^{2} = 13^{2}  + 2 \cdot a \cdot57.46

a = -1.47 m/Sec^{2} (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/Sec^{2} (since same friction force is applied)

v^{2} = 29^{2}  - 2 \cdot 1.47 \cdot S

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Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

4 0
3 years ago
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