Answer:
The final temperature is 85.86°C.
Explanation:
Given that,
Mass of tea = 200 g
Mass of glass = 150 g
Initial temperature = 25°C
We need to calculate the final temperature
When equilibrium is reached, assuming no heat flows to the surroundings
So,
![Q_{glass}+Q_{tea}=0](https://tex.z-dn.net/?f=Q_%7Bglass%7D%2BQ_%7Btea%7D%3D0)
![m_{g}C\Delta T+m_{g}C\Delta T=0](https://tex.z-dn.net/?f=m_%7Bg%7DC%5CDelta%20T%2Bm_%7Bg%7DC%5CDelta%20T%3D0)
We know that,
Specific heat of tea = 1.00 cal/gm° C
Specific heat of tea = 0.20 cal/gm° C
Put the value into the formula
![150\times0.20\times(T_{2}-T_{1})+200\times1.00\times(T_{2}-T_{1})](https://tex.z-dn.net/?f=150%5Ctimes0.20%5Ctimes%28T_%7B2%7D-T_%7B1%7D%29%2B200%5Ctimes1.00%5Ctimes%28T_%7B2%7D-T_%7B1%7D%29)
![30T_{2}-30T_{1}+200T_{2}-200T_{1}=0](https://tex.z-dn.net/?f=30T_%7B2%7D-30T_%7B1%7D%2B200T_%7B2%7D-200T_%7B1%7D%3D0)
![30T_{2}+200T_{2}=30T_{1}+200T_{1}](https://tex.z-dn.net/?f=30T_%7B2%7D%2B200T_%7B2%7D%3D30T_%7B1%7D%2B200T_%7B1%7D)
Put the value of initial temperature
![T_{2}=\dfrac{30\times25+200\times95}{230}](https://tex.z-dn.net/?f=T_%7B2%7D%3D%5Cdfrac%7B30%5Ctimes25%2B200%5Ctimes95%7D%7B230%7D)
![T_{2}=85.86^{\circ}C](https://tex.z-dn.net/?f=T_%7B2%7D%3D85.86%5E%7B%5Ccirc%7DC)
Hence, The final temperature is 85.86°C.
Answer:
Option C.
Polarization takes place!
Answer:
0.000000009006 or 9.006 x 10^-9
Explanation:
0.0000038 x 0.00237 = 0.000000009006 or 9.006 x 10^-9
Explanation:
Below is an attachment containing the solution.
Answer:
bueno lo siguiente es que yo no sé inglés