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andrew-mc [135]
3 years ago
7

The Demon Drop ride at the amusement park falls freely for 1.8 s after

Physics
2 answers:
timofeeve [1]3 years ago
8 0

Answer:

Explanation:

a = -g = -9.80 m/s squared

d o  = 0

v o =  0

t = 1.8s

<h3>unkown:</h3>

d = ?

v = ?

Eddi Din [679]3 years ago
4 0

Answer:

just dont ride it dude, thats legit scary

Explanation:

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In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce
worty [1.4K]

Answer:

b. 0.75 mm

Explanation:

The distance between antinodes d is half the wavelength \lambda. We can obtain the wavelength with the formula v=\lambda f, where f is the frequency given (f=1MHz=1\times10^6Hz) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:

d=\frac{\lambda}{2}=\frac{v}{2f}=\frac{1540m/s}{2(1\times10^6Hz)}=0.00077m=0.77mm

which is very close to the 0.75mm option.

4 0
4 years ago
A sled drops 50 meters in height on a hill. The mass of the rider and sled is 70 kg and the sled is going 10 m/s at the bottom o
navik [9.2K]

Answer:

Efficiency = 10.2 %

Explanation:

Given the following data;

Mass = 70 kg

Height = 50 m

Velocity = 10 m/s

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the efficiency of energy conversion from potential to kinetic;

First of all, we would determine the potential energy;

P.E = mgh

P.E = 70 * 9.8 * 50

P.E = 34300 J

For the kinetic energy;

K.E = ½mv²

K.E = ½ * 70 * 10²

K.E = 35 * 100

K.E = 3500

Therefore, Input energy, I = 34300 J

Output energy, O = 3500 J

Next, we find the efficiency;

Efficiency = O/I * 100

Substituting into the formula, we have;

Efficiency = 3500/34300 * 100

Efficiency = 0.1020 * 100

Efficiency = 10.2 %

4 0
3 years ago
John(body mass=160pounds) is taking off for a long jump. The average ground reaction force Fg at takeoff is 1400 N pointing forw
slega [8]

Answer:

The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)

b) As shown in the FBD the ground reaction forces are:

i) In X direction F_{x}=1400cos(35^{o})=1146.81N

ii) In Y direction F_{y}=1400sin(35^{o})=803.0N

c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under

\sum F_{x}=ma_{x}\\\\\therefore a_{x}=\frac{\sum F_{x}}{m}=\frac{1146.8N}{72.57kg}=15.80m/s^{2}\\\\\sum F_{y}=ma_{y}\\\\\therefore a_{y}=\frac{\sum F_{y}}{m}=\frac{803.00-72.57\times 9.81}{72.57}=1.255m/s^{2}

4 0
3 years ago
A1.200 kg car is sliding down an icy
Triss [41]

Answer:

1585.67N

Explanation:

their are many student who can not get answer on time and step by step answer.so there are

a wats up group of experienced experts who helps you for free with step by step answer.just join this and get answer.

5 0
3 years ago
A positive point charge Q is fixed on a very large horizontal frictionless tabletop. A second positive point charge q is release
UNO [17]

Answer:

As it moves farther and farther away from Q, it's speed will keep increasing.

Explanation:

This is so because the point charges are both positive charges and positive charges repel.

As the charges repel, they do so at an increasing speed.

6 0
3 years ago
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