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3 years ago

What is the de broglie wavelength of a 0.17-kg hockey puck moving at 37 m/s ?

1 answer:

5 0

Im taking lambda as x (wavelength)

m = 0.17 kg

v=37m/s

h=6.62*10^-34m²kg/s

x= h/mv

$x = 6.62 \times 10 ^{ - 34} \div 0.17 \times 37$
$x =1.05 \times {10}^{ - 34} m$

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How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

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4 years ago

4. Finally, convert hemoglobin concentration from g/dL to millimoles per Liter (milliMolar or mM). Hemoglobin has a molecular we

prohojiy [21]

To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water

The molecular weight of Hemoglobin is approximately 16,000 Daltons, when hemoglobin is converted to mM

16000 Dalton = 16000 ( g/mol )

given that 1 Dalton = 1 g/mol

To make 1 molar solution of hemoglobin using 1 liter of water

1 liter = 1000 grams

16000 Dalton = 16000 g/mol

Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.

learn more : brainly.com/question/23517096

8 0

3 years ago

a sample of carbon dioxide is contained in a 250.0mL flask at 0.973 atm and 19.0 celcius. how many molecules of gas are in the s

lbvjy [14]

Answer:n = PV/RT = 0.923 atm x 0.250 L / (0.082057 x 290.75 K) . n = 0.00967. mole 0.00967 mole x 6.22x10^23 molecules/mole = 6.02x10^21 molecules of gas

Explanation:

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3 years ago

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The formula of water, H2O suggests which of the following?

o-na [289]

Answer: A. There are two hydrogen atoms and one oxygen atom per water molecule.

Explanation:

The chemical formular for water "H2O", means it contain 2 hydrogen atoms and one oxygen atom per molecule.

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3 years ago

Find the mass of a metal cylinder that has a volume of 652 cm and a density of<br> 21.45 g/cm

GREYUIT [131]

<h2>Answer: 13985.4 g</h2>

Explanation:

Mass = volume × density

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Explanation:

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3 years ago