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gladu [14]
2 years ago
14

What does the x represent on a motion graph?

Physics
2 answers:
melamori03 [73]2 years ago
8 0

Answer:

Change in position is known as displacement, and is represented by Δd , and change in time is represented by Δt , and velocity is represented by ΔdΔt . In position vs. time graphs, time is the independent variable and is on the x-axis, and position is the dependent variable and is on the y-axis

Explanation:

AnnZ [28]2 years ago
7 0

Change in position is known as displacement, and is represented by Δd , and change in time is represented by Δt , and velocity is represented by ΔdΔt . In position vs. time graphs, time is the independent variable and is on the x-axis, and position is the dependent variable and is on the y-axis

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3 years ago
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The voltage across a conductor is increasing at a rate of 2 volts/min and the resistance is decreasing at a rate of 1 ohm/min. U
Lelechka [254]

Answer:

3.5 amperes

Explanation:

I = E/R

I = ?

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3 0
2 years ago
How do I go about this?
Anna71 [15]

Hi there!

(a)

Recall that:
W = F \cdot d = Fdcos\theta

W = Work (J)
F = Force (N)
d = Displacement (m)

Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

W =248(56)cos(30) = 12027.36 J

To the nearest multiple of ten:
W_A = \boxed{12030 J}

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.

Thus:
\boxed{W_g = 0 J}

(c)
Similarly, the normal force is perpendicular to the displacement, so:
\boxed{W_N = 0 J}

(d)

Recall that the force of kinetic friction is given by:
F_{f} =\mu_k mg

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
W_f = -\mu_k mgd\\W_f = - (0.1)(56)(9.8)(56) = -3073.28 J

In multiples of ten:
\boxed{W_f = -3070 J}

(e)
Simply add up the above values of work to find the net work.

W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3073.28) = 8954.08 J

Nearest multiple of ten:
\boxed{W_{net} = 8950 J}}

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
F_{net} = F_{Ax} - F_f

W = F_{net} \cdot d = (F_{Ax} - F_f)

W = (F_Acos(30) - \mu_k mg)d\\W = (248cos(30) - 0.1(56)(9.8)) * 56 \\\\W = 8954.08 J

Nearest multiple of ten:
\boxed{W_{net} = 8950 J}

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2 years ago
On the ignition switch, the ________ position provides power to electrical equipment including lights, wipers, warning lights an
Katyanochek1 [597]
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8 0
3 years ago
An object with little mass won't require a lot of force to move.
Anna35 [415]

Answer:

True

Explanation:

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7 0
2 years ago
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