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IrinaVladis [17]
4 years ago
9

What do you call the curved upper surface of the water that comely appears when using a graduated cylinder

Physics
2 answers:
zubka84 [21]4 years ago
7 0
I call it the 'meniscus'.
algol [13]4 years ago
6 0
The curved surface of water is called the meniscus
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In two or more complete sentences, explain how you can prove that the number of degrees that the Moon rotates around the Earth e
PolarNik [594]

Answer:

Follows are the explanation to this question:

Explanation:

In this solution, it is defined that there are two principal motions for the moon, which are its revolution as well as rotation. In such a movement called revolution, its Moon is relocating around the Earth, in which the approximate movement of the moon from around earth has an average movement of about 13.2° per day, or 92 degrees every week, that's once in 27.3 days.

3 0
3 years ago
Read 2 more answers
What is the distance write the equation
Sedbober [7]

Answer:

135 m

Explanation:

Given:

vi = 12 m/s

vf = 18 m/s

t = 9s

Find: x

x = ½ (vf + vi) t

x = ½ (18 m/s + 12 m/s) (9 s)

x = 135 m

5 0
3 years ago
Mike enters a revolving door that is not moving. explain where and how mike should push to produce a torque with the least amoun
Bingel [31]

Mike enters a revolving door that is not moving. Mike should push at the edge of the door where it is largest distance from the pivot point in order to produce a torque with the least amount of force. Torque is equal to t = force x distance.

7 0
4 years ago
Read 2 more answers
An athlete needs to lose weight and decides to do it by "pumping iron." (a) How many times must an 60.0 kg weight be lifted a di
Dennis_Churaev [7]

Answer:

a) 37171

b) 20650.5 sec

Explanation:

m = mass of the weight being lifted = 60.0 kg

d = distance by which the weight is lifted = 0.670 m

E = Energy available to burn = 1 lb = 3500 kcal = 3500 x 4184 J

g = acceleration due to gravity = 9.8 m/s²

n = number of times the weight is lifted

Energy available to burn is given as

E = n m g d

3500 x 4184 = n (60) (9.8) (0.670)

n = 37171

b)

T = time period for each lift up = 1.80 s

t = total time taken

Total time taken is given as

t = \frac{n}{T}

t = \frac{37171}{1.80}

t = 20650.5 sec

8 0
3 years ago
With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche
finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 00^{0} while the ball is at 36^{0}

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R=\sqrt{(TUx^2+TUy^2}

R=\sqrt{(9^2+4.7^2}

R=\sqrt{(103)}

R=10.15m/s

the direction

tan\alpha=TUy/TUx

tan\alpha=4.7/9

\alpha=tan^-1(0.522)

\alpha=27.57deg

4 0
3 years ago
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