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3 years ago

A scientist discovers a new type of polymer. What must be true about this polymer?

Chemistry

1 answer:

mixas84 [53]3 years ago

5 0

Answer: Option (D) is the correct answer.

Explanation:

A polymer is a large molecule which contains repeating units.

A polymer forms long chain of atoms which are not necessarily arranged in a ring structure. There are not only double bonds between all the carbon atoms, as there can be single bonds or triple bonds between the atoms of a polymer.

A polymer does not contain many different type of molecules as there are many repeating units and not many molecules in a polymer.

A polymer is made of large molecules with repeating units.

Thus, we can conclude that option (D) is the correct answer.

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Describe the procedure Bourouiba uses to study sneezes.

Gekata [30.6K]

Answer:

The Lydia Bourouiba is recorded is around more than the 100 sneezes and coughs cases.

Explanation:

Lydia Bouroubia was a mathematical physicist who does experiments on sneezes and coughs. She was a leading expert in coughs and sneezes. Sneezing is a phenomenal activity that occurs in our body to excrete the dust particles and germs.

The disease also spread through it. Lydia thought that her research will help people related to their health. It will help in stopping epidemics in public. It is a type of outbreak of disease at a bigger level in the public.

6 0

3 years ago

A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant? 2Al(s) + 3CuSO4(aq) →

vova2212 [387]

Answer:

Copper (II) sulfate

Explanation:

Given reaction is

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Amount of aluminum = 1·25 g

Amount of copper (II) sulfate = 3·28 g

Atomic weight of Al = 26 g

Molecular weight of CuSO4 ≈ 159·5

Number of moles of Al = 1·25 ÷ 26 = 0·048

Number of moles of CuSO4 = 3·28 ÷ 159·5 = 0·021

From the above balanced chemical equation for every 2 moles of aluminum, 3 moles of copper (ll) sulfate will be required

So for 1 mole of Al, 1·5 moles of copper (ll) sulfate will be required

For 0·048 moles of Al, 1.5 × 0·048 moles of copper (ll) sulfate will be required

∴ Number of moles of copper (ll) sulfate required = 0·072

But we have only 0·021 moles of copper (ll) sulfate

As copper (ll) sulfate is not there in required amount, the limiting reactant will be copper (ll) sulfate

∴ The limiting reactant is copper (ll) sulfate

7 0

3 years ago

A gas sample is held at constant temperature. What happens to the pressure of the sample if the volume is doubled and the number

Iteru [2.4K]

Answer:

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

Explanation:

Step 1: Data given

Temperature = constant

Volume will be doubled

Number of molecules will be doubles

Step 2:

p*V = n*R*T

⇒ gas constant and temperature are constant

Initial pressure = n*R*T / V

Initial pressure = 2*R*T/2

Initial pressure = RT

Final pressure = 4*RT / 4

Final pressure = R*T

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

3 0

3 years ago

Solve the quadratic equation 2x^2+13x=15 by method of completing the square<br>

mafiozo [28]

Answer:

x = 1, -7.5

Explanation:

2x² + 13x = 15

Divide the left side of the equation by 2

2(x² + 6.5x) = 15

Divide 6.5 by 2 and square the quotient

6.5/2 = 3.25

3.25² = 10.5625

Add 10.5625 to the left side

2(x² + 6.5x + 10.5625) = 15

Since you have a 2 outside the parentheses, you will be adding 10.5625•2 to the right side.

10.5625 • 2 = 21.125

2(x² + 6.5x + 10.5625) = 36.125

To factor (x² + 6.5x + 10.5625), add b/2 to x

b/2 = 6.5/2 = 3.25

2(x + 3.25)² = 36.125

Divide by 2

(x + 3.25)² = 18.0625

Square root.

(x + 3.25) = √18.0625

x + 3.25 = ±4.25

Subtract 3.25.

x = 4.25 - 3.25 = 1

x = -4.25 - 3.25 = -7.5

x = 1, -7.5

4 0

3 years ago

Part A

velikii [3]

Answer: The layers are ordered by density, with the least dense layer on top, and the densest layer on the bottom.

Explanation:

Plato

5 0

3 years ago