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Misha Larkins [42]

3 years ago

15

Draw graphs representing Boyle’s law, Charles’s law, and Gay-Lussac’s law for a fixed amount of gas. Make sure that you label ea

ch axis and state the assumptions for each law—that is, the variable(s) that is (are) held constant for each law.

1 answer:

dem82 [27]3 years ago

8 0

Answer:

Explanation:

i) represents Boyle s law

ii) represents Charles' law

III) represents Gay Lussacs' law

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The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as 2NI3(s)→N2(g)+3I2(g)

EastWind [94]

Answer:

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

Explanation:

Mass of nitrogen triiodide = 20.0 g

Moles of nitrogen triiodide = $\frac{20.0 g}{395 g/mol}=0.05063 mol$

$2NI_3(s)\rightarrow N_2(g)+3I_2(g), \Delta H_{rxn}=-290.0 kJ$

According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

$\frac{-290.0 kJ}{2}\times 0.05063=-7.34 kJ$

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

3 0

3 years ago

Who were good friends in one day a stranger came<br><br>

insens350 [35]

Answer:

???

Explanation:

5 0

2 years ago

20g of butanedioic acid were shaken with a mixture of 100 cm3 ether and 100 cm3 water at 298K. After titration with standard sod

zlopas [31]

Answer:

I'm Not Good At Chemistry.

Explanation: It's Hard.

8 0

2 years ago

You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?

zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

H = 1g

O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

Mass of O in glucose = $\frac{6x16}{180}$ x 55

= $\frac{96}{180}$ x 55

= 0.53 x 55

Mass of oxygen in glucose = 29.3g

8 0

3 years ago

What is the volume of 35.0 g of propylene glycol if the density of propylene glycol is 1.036 g/ cm3?

Len [333]

Mass = 35.0 g

density = 1.036 g/cm³

volume = ?

therefore:

D = m / V

1.036 = 35.0 / V

V = 35.0 / 1.036

V = 33.784 cm³

answer D

3 0

3 years ago