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garri49 [273]
3 years ago
5

A ball is thrown at a 60.0° angle above the horizontal across level ground. It is thrown from a height of 2.00 m above the groun

d with a speed of 20.0 m/s and experiences no appreciable air resistance. The time the ball remains in the air before striking the ground is closest to_____________.a. 16.2 s.b. 3.07 s.c. 3.32 s.d. 3.53 s.e. 3.64 s.

Physics
1 answer:
klio [65]3 years ago
7 0

Answer:

Option E is correct.

Time the ball remains in the air before striking the ground is closest to 3.64 s

Explanation:

yբ = yᵢ + uᵧt + gt²/2

yբ = 0

yᵢ = 2 m

uᵧ = u sinθ = 20 sin 60 = 17.32 m/s

g = -9.8 m/s², t = ?

0 = 2 + 17.32t - 4.9t²

4.9t² - 17.32t - 2 = 0

Solving the quadratic equation,

t = 3.647 s or t = -0.1112 s

time is a positive variable, hence, t = 3.647 s. Option E.

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Which explanation describes the forces involved for a person to walk down the sidewalk?
Svet_ta [14]

The person walking down the sidewalk follows the newton's third law of motion.

Explanation:

  • A person is able to walk down the sidewalk by using the reaction forces from the ground.
  • In simple term, feet pushes the ground and the reaction forces makes the feet able to walk.
  • Another important force included in the walking mechanism is friction. With out friction one cannot walk down the sidewalks.
  • Hence the forces involved in the walking of a person down the sidewalk are:
  1. Friction force
  2. Action and reaction force between ground and person's feet.
4 0
3 years ago
An assistant for a football team carries a 26.0 kg cooler of water from the top row of the stadium, which is a distance h = 17.5
frozen [14]

The weight of the cooler is (mg). That's (26)(9.8) = 254.8 Newtons.

Its gravitational potential energy while it's up in the top row is (mgh). That's (254.8)(17.5) = 4,459 Joules.

That's how much work it took to get the cooler up to the top row, and that's the energy it gives up when it moves back down to the bench.

In order to bring it down . . .

-- Gravity does 4,459 joules of work on the cooler.

-- The team assistant does NEGATIVE 4,459 joules of work on it.

6 0
3 years ago
a car with a mass of 1.2×10^3 kilograms is moving at a speed of 18 meters/second. it is hit by a truck from behind and it's spee
garik1379 [7]
I = Delta p

I = Impulse
Delta p = Momentum variation

Delta p = pf - po

Pf = Final momentum
Po = Initial momentum

p = m x v

M = Mass
V = Velocity

Delta p = (m x Vf) - (m x Vo)

I = 1.2 x 10^3 x 20 - 12 x 10^2 x 18
I = 2.4 x 10^4 - 216 x 10^2
I = 2.4 x 10^4 - 2.16 x 10^4
I = 0.24 x 10^4
I = 24 x 10^2 Newtons x seconds (N x s)

Answer: The value of impulse is 24 x 10^2 Newtons x seconds (N x s).
8 0
3 years ago
Please please help i need to finish this test
salantis [7]

Answer:

-4.4 m/s

Explanation:

Since the ball is thrown upward, we can ignore the horizontal velocity. This means that the vertical velocity is 25 m/s. The vertical acceleration is -9.8 m/s^2 (g). This means that after 3 seconds, the velocity would've decreased by 9.8 m/s^2 * 3 s. This is 29.4 m/s.

This should be subtracted from the initial velocity:

25 m/s - 29.4 m/s = -4.4 m/s

Hope this helps!

5 0
3 years ago
HELP ME ILL MARK YOU THE BRAINLIEST
OleMash [197]

Option C: Later in the day, less power is developed in lifting each box

7 0
3 years ago
Read 2 more answers
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