To find how many moles of the gas you can use ideal gas formula. Remember to change the temperature unit to Kelvin. Since the pressure using kpa, the constant used would be 8.314 kpa*L / mol*K
PV=nRT
n= PV/RT
n= 17,250 kpa * 20 / 8.314 * (24+273.15)K
n=139.64moles
Answer:
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
Explanation:
Mass of acetanilide to be dissolved in hot water = 2.1 g
Mass of hot water to be used = m
Solubility of acetanilide = 55 g/L
This means that 55 grams of acetanilide dissolves in 1 L of hot water.
Then 1 grams of acetanilide will dissolve in :
0.0382 L = 0.0382 × 1000 mL =38.2 mL
1 L = 1000 mL
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
When we have the balanced reaction equation is:
H2(g) + CO2(g) ↔ H2O(g) + CO (g)
a) first, to calculate ΔG° for the reaction:
we will use this formula:
ΔG° = -RT㏑Kp
when R is R- rydberg constant = 8.314J/mol.K
and T is the temperature in Kelvin = 2000 K
and Kp = 4.4
so, by substitution:
ΔG° = - 8.314 *2000 *㏑4.4
= - 24624 J/mol = - 24.6 KJ/mol
b) to calculate ΔG so, we will use this formula:
ΔG = ΔG° + RT㏑Qp
So we need first, to get Qp from the reaction equation:
when Qp = P products / P reactants
= PH2O*PCO / PH2 * PCO2
= (0.66 atm * 1.2 atm) / (0.25 * 0.78)
= 4.1
so by substitution:
ΔG = -24624 + 8.314*2000*㏑4.1
= -1162 J/mol = - 1.16 KJ/mol
Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. Temperature is measured with a thermometer.
