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The correct answer to the problemis velocity. I did the test.
Answer:
Explanation:
Reaction force of inclined surface
R = mgcos30
=60 x 9.8 x .866
= 509 N
Force of kinetic friction
= .12 x 509
= 61.08 N
b )
net force downwards = mgsinθ - μmgcosθ
acceleration = g sinθ - μgcosθ
9.8 sin30 - .12 x 9.8 x cos30
= 4.9 - 1.018
a= 3.88 m /s²
c )
v² = 2as
= 2 x 3.88 x 20
v = 12.46 m /s
Answer:
1.26 secs.
Explanation:
The following data were obtained from the question:
Force (F) = 20 N
Extention (e) = 0.2 m
Mass (m) = 4 Kg
Period (T) =.?
Next, we shall determine the spring constant, K for spring.
The spring constant, K can be obtained as follow:
Force (F) = 20 N
Extention (e) = 0.2 m
Spring constant (K) =..?
F = Ke
20 = K x 0.2
Divide both side by 0.2
K = 20/0.2
K = 100 N/m
Finally, we shall determine the period of oscillation of the 4 kg object suspended on the spring. This can be achieved as follow:
Mass (m) = 4 Kg
Spring constant (K) = 100 N/m
Period (T) =..?
T = 2π√(m/K)
T = 2π√(4/100)
T = 2π x √(0.04)
T = 2π x 0.2
T = 1.26 secs.
Therefore, the period of oscillation of the 4 kg object suspended on the spring is 1.26 secs.
Answer:
σ =4.180×10^{-9} C/m^2
Explanation:
electric field due to non conducting sheet is
![E=\frac{\sigma}{2\epsilon_0}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B%5Csigma%7D%7B2%5Cepsilon_0%7D)
the force acting on the piece of Styrofoam
Eq= mg
⇒E= mg/q
now,
![\frac{mg}{q} = \frac{\sigma}{2\epsilon_0}](https://tex.z-dn.net/?f=%5Cfrac%7Bmg%7D%7Bq%7D%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%5Cepsilon_0%7D)
⇒![\sigma= \frac{2mg\epsilon_0}{q}](https://tex.z-dn.net/?f=%5Csigma%3D%20%5Cfrac%7B2mg%5Cepsilon_0%7D%7Bq%7D)
![\sigma= \frac{2\times0.013\times9.81\times8.85\times10^{-12}}{5.40\times10^{-4}}](https://tex.z-dn.net/?f=%5Csigma%3D%20%5Cfrac%7B2%5Ctimes0.013%5Ctimes9.81%5Ctimes8.85%5Ctimes10%5E%7B-12%7D%7D%7B5.40%5Ctimes10%5E%7B-4%7D%7D)
charge per unit area (in C/m2) on the plastic sheet σ =4.180×10^{-9} C/m^2