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Sedaia [141]
3 years ago
11

In a jigsaw classroom: A. students choose their own groups. B. students have to depend on one another to learn the required info

rmation. C. students learn the material on their own. D. students change groups every day​
Physics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

B. students have to depend on one another to learn the required information.

Explanation:

It's kinda like puzzles having pieces and you use them to put together. So they can use this information to figure out what they're trying to solve with the information. -I hope this helped!

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a/ Compute the quantity of heat released by 25.0 g of steam initially at 100.0oC, when it is cooled to 34.0°C and by 25.0 g of w
Svetach [21]

Answer:

When put into steam

Explanation:

When a certain amount of steam at boiling temperature condenses (turning into water), the amount of heat released is

Q_1 = m\lambda_v

where in this case

m = 25.0 g = 0.025 kg is the mass of steam at 100.0°C

\lambda_v=2.256\cdot 10^6 J/kg is the latent heat of vaporization of water

So,

Q_1=(0.025)(2.256\cdot 10^6)=56400 J

Instead, the amount of heat released when the water at 100.0°C is cooled down to 34.0°C is given by

Q_2=mC\Delta T

where

m = 25.0 g = 0.025 kg is the mass of water

C=4.19\cdot 10^4 J/kg K is the specific heat of water

\Delta T=100-34=66^{\circ}C is the change in temperature

Therefore,

Q_2=(0.025)(4.19\cdot 10^3)(66)=6913 J

Since Q_1>Q_2, we can say that your hand will burn more in the first case.

5 0
3 years ago
A student solving a physics problem for the range of a projectile has obtained the expression
Alika [10]

Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

R=\dfrac{v_o^2\ sin2\theta}{g}..............(1)

v_o=37.2\ m/s

\theta=14.1^{\circ}

g=9.8\ m/s^2

The range can be calculated using equation (1). Putting the values of all parameters we get :

R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.

6 0
3 years ago
The force of gravity on you is greatest when you are standing _____.
I am Lyosha [343]
The force of Earth's gravity on you is greatest when you stand as
close as you can to the center of the Earth (but not underground).

From the choices listed, that would be (c).
8 0
3 years ago
The useful power output from the motor is 1.5 kW
zaharov [31]

Answer:

t = 300 seconds

Explanation:

Given that,

The power output of the motor, P = 1.5 kW

Energy transferred = 450 000 J

Power is given by work done per unit time. So,

P=\dfrac{W}{t}\\\\t=\dfrac{W}{P}\\\\t=\dfrac{450 000}{1.5\times 10^3}\\\\t=300\ s

So, it will take 300 seconds for the motor.

3 0
3 years ago
A 0.500 kg mass is oscillating on a
Norma-Jean [14]

Answer:

3.6m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5Kg

Spring constant (K) = 330N/m

Energy = 3.24J

Velocity (v) =..?

The velocity of the mass can be obtained as follow:

E = ½mv²

3.24 = ½ × 0.5 × v²

3.24 = 0.25 × v²

Divide both side by 0.25

v² = 3.24/0.25

Take the square root of both side

v = √(3.24/0.25)

v = 3.6m/s

Therefore, the speed of the mass is 3.6m/s

6 0
3 years ago
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