Answer:
4.45×10¯¹¹ N
Explanation:
From the question given above, the following data were obtained:
Mass of ball (M₁) = 4 Kg
Mass of bowling pin (M₂) = 1.5 Kg
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Distance apart (r) = 3 m
Force of attraction (F) =?
The force of attraction between the ball and the bowling pin can be obtained as follow:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 4 × 1.5 / 3²
F = 4.002×10¯¹⁰ / 9
F = 4.45×10¯¹¹ N
Therefore, the force of attraction between the ball and the bowling pin is 4.45×10¯¹¹ N
<span>Hormone: a chemical message released in the bodyby cells and glands that affects other cells in an organism. Hypothalamus: a part of the brain thatcontrols things like thirst, hunger, body temperature, and the release of many hormones.</span>
Answer:
0.5m/s^2
Explanation:
We can use the formula [ F = ma ] but solve for "a" since that is what we are looking for.
F = ma
F/m = a
We know the net force and mass so substitute those values and simplify.
500/1000 = 0.5m/s^2
Best of Luck!
Answer:
a)188.65m
b)154.35m
c)243.7m
Explanation:
Given data:
(a) The distance from the kicker to each of the 2 spectators is given by:
where,
v= speed of sound
=time taken for the sound waves to reach the ears
m
(b)
where,
v= speed of sound
=time taken for the sound waves to reach the ears
(c)As the angle b/w slight lines from the two spectators to the player is right angle,
hypotenuse=the distance b/w 2 spectators
and, the slight lines are the other 2 lines
