Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths f
1 answer:
Answer:
T= 563/4= 140.75 nm
Explanation:
Soap bubbles can display impressive colors.
In a bubble there are two surfaces the first surface has a phase shift of 180° and second surface has 0° phase shift.
so total
wavelength λ= 2π
hence wavelength λ/2
Also λ=
= 562.9921≅563 nm
also wall thickness T
T= λ/4
⇒T= 563/4= 140.75 nm
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Question :
If a body acquires a charge of -0.02 C, has it gained or lost electrons? Many?
Solution :
We know, charge gained is shown by negative sign.
Since, charged acquired is given as -0.02 C .
Therefore, it is body has gained electrons.
Now, number of electrons is given by :
Hence, this is the required solution.
Answer:
v ’= 21.44 m / s
Explanation:
This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s
f ’= f (v + v₀) / (v-)
where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer
in this exercise both the source and the observer are moving, we will assume that both have the same speed,
v₀ = v_{s} = v ’
we substitute
f ’= f (v + v’) / (v - v ’)
f ’/ f (v-v’) = v + v ’
v (f ’/ f -1) = v’ (1 + f ’/ f)
v ’= (f’ / f-1) / (1 + f ’/ f) v
v ’= (f’-f) / (f + f’) v
let's calculate
v ’= (3400 -3000) / (3000 +3400) 343
v ’= 400/6400 343
v ’= 21.44 m / s