Question

Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths from the bubbles' walls. For a soap solution with an index of refraction of 1.27, find the minimum wall thickness that will enhance the reflection of light of wavelength 715 nm in air.

Answer 1

Answer:

T= 563/4= 140.75 nm

Explanation:

Soap bubbles can display impressive colors.

In a bubble there are two surfaces the first surface has a phase shift of 180° and second surface has 0° phase shift.

so total $\pi$

wavelength λ= 2π

hence wavelength λ/2

Also λ= $\frac{715}{1.27}$

= 562.9921≅563 nm

also wall thickness T

$2T= \frac{λ}{2}$

T= λ/4

⇒T= 563/4= 140.75 nm