All categories

2 years ago

Determine the number of moles within a sample of 10g of propane(C3H8). Round your answer to 2 decimal places with proper units.

Chemistry

1 answer:

a_sh-v [17]2 years ago

7 0

Given :

10 gram sample of propane( C₂H₈ ).

To Find :

The number of moles of propane in given sample.

Solution :

Molecular mass of propane, M = (2 × 12) + ( 1 × 8 ) gram/mol

M = 32 gram/mol

We know, number of moles is given by :

Number of moles, n = m/M

n = 10/32 mol

n = 0.3125 mol

Therefore, number of moles in given sample is 0.3125 mol.

You might be interested in

suppose you are testing the buoyancy of different objects . study the table and choose object with the greatest buoyant force

Alika [10]

The formula to calculate buoyant force (FB) states that the upward force exerted on an immersed object is equal to the density (ρ ) of the fluid multiplied by both the fluid’s displaced volume (V) and the gravitational acceleration (g), or
FB = ρ x V x g.
I hope that helped with what you're doing.
You can also try water displacement in a graduated cylinder.

7 0

3 years ago

Write a balanced equation for the combination reaction described, using the smallest possible integer coefficients. When diphosp

WITCHER [35]

Answer:

P₂O₅ + 3H₂O => 2H₃PO₄

Explanation:

Nothing to explain.

6 0

2 years ago

When heating test tubes, always slant them away from yourself and others. True False

Leni [432]

Answer:

true

Explanation:

3 0

3 years ago

At a given temperature, K = 1.3x10^-2 for the reaction:

son4ous [18]

Answer:

a) 0.11

b)76.9

c) 8.8

d) 1.7*10^-4

Explanation:

Step 1: Data given

K = 1.3 * 10^-2 for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g)

Step 2: Formula of K

aA(g) + bB(g) ⇌ cC(g) + dD(g)

K = [C]^c *[D]^d / [A]^a * [B]^b

K = 1.3 * 10^-2 = [NH3]² / [H2]³*[N2]

Step 3:

a) 1/2N2 + 3/2H2(g) ⇌ NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

1/2N2 + 3/2H2(g) ⇌ NH3(g) =>K' = $\sqrt{K}$

K' = $\sqrt{1.3*10^-2}$ = 0.11

b. 2NH3(g) ⇌ N2(g) + 3H2(g)

N2(g) + 3H2(g) ⇌ 2NH3

2NH3(g) ⇌ N2(g) + 3H2(g) =>K' = 1/K

K' = 1/(1.3*10^-2) = 76.9

c. NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)

N2(g) + 3H2(g) ⇌ 2NH3

NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)

=>K' = $\frac{1}{\sqrt{K} }$

K' = $\frac{1}{\sqrt{1.3*10^-2} }$

K' = 8.8

d. 2N2(g) + 6H2(g) ⇌ 4NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

2N2(g) + 6H2(g) ⇌ 4NH3(g)

K' = K²

K' = (1.3*10^-2)²

K' = 1.7 *10 ^-4

4 0

2 years ago

How many moles of MgCl2 are produced from 4 moles of HCl

Karolina [17]

Answer:

2 moles of MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Mg + 2HCl —> MgCl2 + H2

Now, we can determine the number of mole MgCl2 produced from 4 moles of HCl as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 1 mole of MgCl2.

Therefore, 4 moles of HCl will react to produce = (4 x 1)/2 = 2 moles of MgCl2.

Therefore, 2 moles of MgCl2 were produced from the reaction of 4 moles of HCl.

5 0

3 years ago