In science and physics what is the standard unit of measure for speed?

Propane (c3h8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below. c3h8 5o2 → 3

ahrayia [7]

The amount of oxygen will be 22.29 gm required to produce 37.15 g co₂.

<h3>What is a chemical reaction?</h3>

One or more compounds, known as reactants, are transformed into one or more distinct substances, known as products. Such a process is known as a chemical reaction.

Given reaction;

$\rm C_3h_8 +5O_2 }\rightarrow 3CO_2 +4H_2O$

The quantity of oxygen is x and the quantity of carbon dioxide is y then the ratio of their composition is found as;

5x=3y

5x=37.15

x=3×37.15/5

x=22.29 gm

Hence the amount of oxygen will be 22.29 gm

To learn more about the chemical reaction refer to the link;

brainly.com/question/22817140

#SPJ1

3 0

2 years ago

List and define three types of intermolecular forces and identify which types of molecules each forces affects.

Zigmanuir [339]

Van der waals forces

Hydrogen bonding

Crystal lattice forces

Explanation:

Intermolecular forces exists between molecules.

Van der waals forces are weak attractions that joins non-polar and polar molecules together. London dispersion forces occurs between non-polar molecules(polar) and noble gases. Dipole -dipole attraction occurs between polar molecules. Van der waal forces occurs in graphite layers, HCl e.t.c
Hydrogen bonding is force of attraction between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom. Examples occur in water.
Ionic crystal lattice forces are strong electrostatic forces of attraction between oppositely charged ions arranged into a crystal lattice of ionic compounds. For example in NaCl

Learn more:

Intermolecular forces brainly.com/question/3622116

#learnwithBrainly

3 0

3 years ago

Plzz answer this question correctly

zvonat [6]

Answer:

B

Explanation:

F= m×a

450N = 1.5kg × a

450/1.5 = a

a=300m/s²

IM NOT SURE THO

4 0

3 years ago

Can someone please help a struggling physics student?

zhenek [66]

<u><em>What is the maximum height the ball will reach in the air?</em></u>

Kinematics equation used:

$v_f^2=v_i^2+2ad$ , where $v_f$ is final velocity, $v_i$ is initial velocity, $a$ is acceleration, and $d$ is distance travelled. From SI units, velocity should be in $m/s$ , acceleration should be in $m/s^2$ , and distance should be in $m$

We're given that the initial velocity is 12.0 m/s in the y-direction. At the maximum height, the vertical velocity of the ball will be 0 m/s, otherwise it would not be at maximum height. This is our final velocity.

The only acceleration in the system is acceleration due to gravity, which is approximately $9.8\:\mathrm{ m/s^2}$ . However, the acceleration is acting down, whereas the ball is moving up. To express its direction, acceleration should be plugged in as $-9.8\:\mathrm{m/s^2}$ . We have three variables, and we are solving for the fourth, which is distance travelled. This will be the maximum height of the ball.

Substitute $v_i=12$ , $v_f=0$ , $a=-9.8$ to solve for $d$ :

$0^2=12^2+2(-9.8)(d),\\0=144-19.6d,\\-19.6d=-144,\\d=\frac{-144}{-19.6}=7.34693877551\approx \boxed{7.35\text{ m}}$

<u><em>What is the velocity of the ball when it hits the ground?</em></u>

This question tests a physics concept rather than a physics formula. The vertical velocity of the ball when it hits the ground is equal in magnitude but opposite in direction to the ball's initial vertical velocity. This is because the ball spends equal time travelling to its max height as it does travelling from max height to the ground (ball is accelerating from initial velocity to 0 and then from 0 to some velocity over the same distance and time). Since the ball has an initial vertical velocity of +12.0 m/s, its velocity when it hits the ground will be $\boxed{-12.0\text{ m/s}}$ . (The negative sign represents the direction. Because velocity is a vector, it is required.)

<u>**Since my initial answer exceeds the character limit, I've attached the first question to Part B as an image. Please refer to the attached image for the answer and explanation to the first question of Part B. Apologies for the inconvenience.**</u>

<u><em>What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).</em></u>

This question uses a similar concept as the second question of Part A. The vertical velocity of the ball at launch is equal in magnitude but opposite in direction to the ball's final velocity. The horizontal component is equal in both magnitude and direction throughout the entire launch, since there are no horizontal forces acting on the system. Therefore, the angle below the horizontal of the ball's velocity when it hits the ground is equal to the angle of the ball to the horizontal at launch.

To find this, we need to use basic trigonometry for a right triangle. In any right triangle, the tangent/tan of an angle is equal to its opposite side divided by its adjacent side.

Let the angle to the horizontal at launch be $\theta$ . The angle's opposite side is represented by the vertical velocity at launch (12.0 m/s) and the angle's adjacent side is represented by the horizontal velocity at launch (2.3 m/s). Therefore, we have the following equation:

$\tan \theta=\frac{12.0\text{m/s}}{2.3\text{ m/s}}$

Take the inverse tangent of both sides:

$\arctan (\tan \theta)=\arctan (\frac{12.0}{2.3})$

Simplify using $\arctan(\tan \theta)=\theta \text{ for }\theta \in (-90^{\circ}, 90^{\circ})$ :

$\theta=\arctan(\frac{12.3}{2.3}),\\\theta =79.14989537\approx \boxed{79.15^{\circ}}$

We can express our answer by saying that the direction of the velocity of the ball when it hits the ground is $\boxed{\text{approximately }79.15^{\circ} \text{ below the horizontal}}$ or $\boxed{\text{approximately }-79.15^{\circ} \text{ to the horizontal}}$ .

5 0

3 years ago

What is one of Kepler's laws of planetary motion?

iragen [17]

Answer:

a. Planets move on elliptical orbits with the Sun at one focus.

Explanation:

Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).

The three (3) laws published by Kepler include;

I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.

II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.

Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.

III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Hence, one of Kepler's laws of planetary motion states that planets move on elliptical orbits with the Sun at one focus. This is his first law of planetary motion.

4 0

3 years ago