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Alex_Xolod [135]
3 years ago
13

Write the equation for the reaction described: A solid metal oxide, Ag2O, and hydrogen are the products of the reaction between

metal and steam. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
8 0

Answer:

2Ag + H2O -----> Ag2O + 2H

Explanation:

2Ag + H2O -----> Ag2O + 2H is the equation of the reaction between metal and steam. Silver reacts with water (steam) forming silver oxide and hydrogen gas. When the metals react with steam it produces the solid metal oxide and hydrogen gas. On the surface o metals, a protective layer of aluminium oxide is formed that keeps water away from the metal so we can say that silver oxide and hydrogen are formed from the reaction of silver metal and steam.

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<span>The object that was trying to be oxidized would end up being reduced. There would be no net reaction otherwise. The KCl would have simply melted after a long enough time and with the application of enough heat to the crucible.</span>
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What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?
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Answer:

Explanation:

Na + Cl2 —> NaCl

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3 years ago
One significant difference between gases and liquids is that:
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The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr
jenyasd209 [6]

Answer : The final temperature of the water is, 22.5166^oC

Explanation : Given,

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First we have to calculate the moles of benzene.

\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives \frac{6542 kJ}{2}\times 0.1103=360.7913kJ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})

where,

q_w = heat released = 360.7913 kJ = 36079.13 J

m_w = mass of water = 5691 g

c_w = specific heat of water= 4.18J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 21^oC

Now put all the given values in the above formula, we get:

36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)

T_{final}=22.5166^oC

Therefore, the final temperature of the water is, 22.5166^oC

8 0
4 years ago
Fe2O3 + H2 --&gt; Fe + H2O
sveticcg [70]
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One mole of dihydrogen is required to form one mole of iron, hence you'll need 0.179*1.00=0.179g of dihydrogen.

B) Likewise : 2.50g of Iron is \frac{2.50}{55.8}=44.8mmol of Iron, hence we'll need 44.8*(3*16+2*55.8)=7.15g of Fe2O3.
4 0
4 years ago
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