Explanation:
2 ClO2 (aq) + 2OH- (aq)→ ClO3- (aq) + ClO2- + H2O (l)
The data is given as;
Experiment [ClO2] (M) [OH-] (M) Initial Rate (M/s)
1 0.060 0.030 0.0248
2 0.020 0.030 0.00276
3 0.020 0.090 0.00828
a) Rate law is given as;
Rate = k [ClO2]^x [OH-]^y
From experiments 2 and 3, tripling the concentration of [OH-] also triples the rate of the reaction. This means the reaction is first order with respect to [OH-]
From experiments 1 and 2, when the [ClO2] decreases by a factor of 3, the rate decreases by a factor of 9. This means the reaction is second order with respect to [ClO2]
Rate = k [ClO2]² [OH-]
b. Calculate the value of the rate constant with the proper units.
Taking experiment 1,
0.0248 = k (0.060)²(0.030)
k = 0.0248 / 0.000108
k = 229.63 M-2 s-1
c. Calculate the rate when [ClO2] = 0.100 M and [OH-] = 0.050 M.
Rate = 229.63 [ClO2]² [OH-]
Rate = 229.63 (0.100)²(0.050)
Rate = 0.1148 M/s
This problem is providing us with the mass of sulfur dioxide and the molecules contained are required. At the end, the result turns out to be 3.252x10²³ molecules, according to:
<h3>Avogadro's number:</h3>
In chemistry, we use the Avogadro's number in order to successfully perform mole-mass-particles calculations. Defined as 6.022x10²³, it provides the number of atoms, molecules and ions in one mole of the substance.
In this case, in order to obtain the result, one first calculates the moles in 34.61 grams of sulfur dioxide and then utilize the Avogadro's number to obtain the number of molecules as shown below:
Learn more about Avogadro's number: brainly.com/question/20091306
Dark energy and dark matter seem over analyzed, although they are no different than gravity and wind. Dark energy can be the pulling caused by black holes, stars, and large planets. Dark matter also is just the effect of cosmic dust and debris pushed from explosions but also pulling caused by distant gravitational bodies.
Answer:
Phenolphthalein is an indicator. It is pink in alkaline solutions and turns colourless as the pH decreases.
It can be used to measure the activity of the enzyme lipase on the breakdown of lipids.
Samples of milk containing phenolphthalein were incubated with lipase at different temperatures.
The time taken for the phenolphthalein to turn colourless was recorded and used to calculate the rate of enzyme activity.
Figure 10 shows these results.
Picture
(a) (i) Explain why phenolphthalein turns colourless when lipase breaks down the lipids in milk. (2)
(ii) Describe the effect of temperature on the activity of lipase, as shown in Figure 10. (2)
(iii) Explain why the activity of lipase changes above a temperature of 40°C. (2)
(b) A student investigated the time taken for amylase to breakdown a 10% starch solution into glucose at 37°C. The student repeated the investigation five times.
D. two identical daughter cells Diploid cells
Mitosis occurs more in your body since it changes, modifies and requires cell division at maximum rate in many useful situations with the stand to a particular system and organ.
