do you have anymore numbers to add to this problem??
Q1. -------- a specific way that a quantity may increase over time
1. Exponential growth
2. Biotic
3. Trait
4. Succession
Answer:
1. Exponential growth
Explanation:
Exponential growth is a specific way that a quantity may increase over time. The instantaneous rate of change of a quantity with respect to time is proportional to the quantity itself. When growth becomes more rapid in relation to the growing total number, then it becomes exponential.
Example: Latest updates of COVID-19. For today, the number of infected people cases from COVID-19 is 190,000. By observing the graph, to reach 100,000 the number of infected patient cases, it took 3 months and the other 90,000 patients were infected in just 15 days.
Q2. ------- is the inherent inclination of a living organism towards a particular complex behavior.
1. Abiotic
2. Biotic
3. Innate behavior
Answer:
3. Innate behavior
Explanation:
Innate behavior is behavior that occurs naturally in all members of a species. These behaviors do not have to be learned or practiced.
Example: When a human baby born, he already knows how to suck mother breast to get milk. He never learned before. As he grew up, he knows how to grasp things.
Answer:

Explanation:
Hello there!
In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

Regards!
Answer:
I hope this is it. I'm not really sure.
Answer:
3.64g
Explanation:
Given parameters:
Mass of NH₃ = 18.1g
Mass of Cu₂O = 90.4g
Unknown:
Limiting reactant = ?
Mass of N₂ formed = ?
Solution:
The reaction equation is given as:
Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;
Number of moles =
Molar mass of Cu₂O = 2(63.6) + 16 = 143.2g/mol
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles of Cu₂O =
= 0.13moles
Number of moles of NH₃ =
= 5.32moles
From this reaction;
1 mole of Cu₂O combines with 2 mole of NH₃
So 0.13moles of Cu₂O will combine with 0.13 x 2 mole of NH₃
= 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;
Mass of N₂;
Mass = number of moles x molar mass
1 mole of Cu₂O will produce 1 mole of N₂
0.13 mole of Cu₂O will produce 0.13 mole of N₂
Mass = 0.13 x (2 x 14) = 3.64g