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Stels [109]
3 years ago
11

Describe binary fission with amoeba.​

Physics
1 answer:
kirza4 [7]3 years ago
6 0
Amoeba reproduce by the common asexual reproduction method called binary fission
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I need help with all of these questions
Sedbober [7]

Answer:

This was my best estimation of the answers

7 0
3 years ago
Which is NOT one of the four principals of Dalton’s atomic theory?
Gre4nikov [31]

Answer:

Your answer would be letter <em><u>B</u></em><em><u>.</u></em><em><u> </u></em><em><u>Electrons</u></em><em><u> </u></em><em><u>orbit</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>nucleus</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>energy</u></em><em><u> </u></em><em><u>level</u></em><em><u>.</u></em>

Explanation:

Hope it helps..

Just correct me if I'm wrong, okay?

But ur welcome!!

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8 0
3 years ago
Read 2 more answers
To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where
BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

\int E.dA = \frac{q}{\epcilon_0}

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

q = \int \rho dV

q = \rho * \pi r^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r}{2 \epcilon_0}

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

q = \int \rho dV

q = \rho * \pi r_0^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r_0^2}{2 \epcilon_0 r}


7 0
3 years ago
While riding in a hot air balloon, which is steadily decreasing at a speed of 1.14 m/s, you accidentally drop your cell phone. H
Ilia_Sergeevich [38]

Answer:

The distance covered by the balloon is 47.52 meters.

Explanation:

Given that,

Initial speed of the balloon, u = 1.14 m/

Let us assumed we need to find the distance covered by the balloon after t = 3 second. Let d is the distance covered by the balloon. It can be given by :

d=ut+\dfrac{1}{2}at^2

Here, a = g

d=ut+\dfrac{1}{2}gt^2

d=1.14\times 3+\dfrac{1}{2}\times 9.8\times (3)^2

d = 47.52 meters

So, the distance covered by the balloon is 47.52 meters. Hence, this is the required solution.

4 0
3 years ago
Which statement is true according to Newton's second law of motion? A. An object accelerates in the direction opposite to the di
Tom [10]

Answer:

C. An object accelerates in the same direction as that of the force applied.

Explanation:

 An object accelerates in the same direction as that of the force applied.

4 0
3 years ago
Read 2 more answers
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