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Andreas93 [3]
3 years ago
15

A large spherical tank contains gas at a pressure of 400 psi. The tank is constructed of high-strength steel having a yield stre

ss in tension of 80 ksi. For volume requirements, the inner diameter of the tank is 45-ft. Determine the required thickness (to the nearest ¼ inch) of the wall of the tank if a factor of safety of 3.0 with respect to yielding is required.
Engineering
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

t=2.025 inches

Explanation:

Given that

P = 400 Psi

Yield stress ,σ = 80 ksi

Diameter ,d= 45 ft

We know that

1 ft = 12 inches

d= 540 inches

Factor of safety ,K= 3

The required thickness given as

\dfrac {Pd}{4t}=\dfrac{\sigma}{K}

t=thickness

\dfrac {PdK}{4\sigma}=t

\dfrac {400\times 540\times 3}{4\times 80\times 1000}=t

t=2.025 inches

Therefore thickness will be 2.025 inches.

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Answer:

Total BF for the interior wall is 7.50BD

Explanation:

Given Data:

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1 BF (Board feet) = 1 ft x 1 ft x 1 inch

Since there are total three plates at top and bottom, we have to deduct their thickness from wall height to calculate height of stud.

Height of stud = 8’ – 3 x 2” = 7’6” = 7.5 ft

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3 years ago
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Answer: Attached below is the well written question and solution

answer:

i) Attached below

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Explanation:

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2 years ago
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Answer:

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Explanation:

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Kd = 3.3 L/kg (toluene)

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K = 2.9x10⁻⁵m/s

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