Answer:
The correct option is d ( Neither A nor B)
Explanation:
Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.
Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.
This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong
Since option a and b are incorrect and c is invalid.
Answer:
minimum length of a surface crack is 15.043 mm
Explanation:
given data
strain fracture toughness K = 78 MPa
tensile stress = 345 MPa
Y = 1.04
to find out
minimum length of a surface crack
solution
we find here length of critical interior flaw from formula that is
α =
....................1
put here value we get
α = ![\frac{1}{\pi} (\frac{78*\sqrt{10^3} }{345*1.04})^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Cpi%7D%20%28%5Cfrac%7B78%2A%5Csqrt%7B10%5E3%7D%20%7D%7B345%2A1.04%7D%29%5E2)
α = 15.043 mm
so minimum length of a surface crack is 15.043 mm
Answer:
The principal stresses are σp1 = 27 ksi, σp2 = -37 ksi and the shear stress is zero
Explanation:
The expression for the maximum shear stress is given:
![\tau _{M} =\sqrt{(\frac{\sigma _{x}^{2}-\sigma _{y}^{2} }{2})^{2}+\tau _{xy}^{2} }](https://tex.z-dn.net/?f=%5Ctau%20_%7BM%7D%20%3D%5Csqrt%7B%28%5Cfrac%7B%5Csigma%20_%7Bx%7D%5E%7B2%7D-%5Csigma%20_%7By%7D%5E%7B2%7D%20%20%7D%7B2%7D%29%5E%7B2%7D%2B%5Ctau%20_%7Bxy%7D%5E%7B2%7D%20%20%20%20%7D)
Where
σx = stress in vertical plane = 20 ksi
σy = stress in horizontal plane = -30 ksi
τM = 32 ksi
Replacing:
![32=\sqrt{(\frac{20-(-30)}{2} )^{2} +\tau _{xy}^{2} }](https://tex.z-dn.net/?f=32%3D%5Csqrt%7B%28%5Cfrac%7B20-%28-30%29%7D%7B2%7D%20%29%5E%7B2%7D%20%2B%5Ctau%20_%7Bxy%7D%5E%7B2%7D%20%20%7D)
Solving for τxy:
τxy = ±19.98 ksi
The principal stress is:
![\sigma _{x}+\sigma _{y} =\sigma _{p1}+\sigma _{p2}](https://tex.z-dn.net/?f=%5Csigma%20_%7Bx%7D%2B%5Csigma%20_%7By%7D%20%3D%5Csigma%20_%7Bp1%7D%2B%5Csigma%20_%7Bp2%7D)
Where
σp1 = 20 ksi
σp2 = -30 ksi
(equation 1)
equation 2
Solving both equations:
σp1 = 27 ksi
σp2 = -37 ksi
The shear stress on the vertical plane is zero
The first one is d or the 4th answer choice and the second one is false. Hope this helps!
Express it in standard form and apply the basic indices laws to simplify