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AlladinOne [14]
3 years ago
11

Suppose that an electromagnetic wave is traveling toward the east. At one instant at a given point, the electric field vector po

ints upward. What is the direction of the magnetic field at this same given point and instant in time? Is it:
1.) downward
2.) east
3.) south
4.)north
5.)west
6.)upward
Physics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer: east

Explanation: A propagating electromagnetic wave in space has it electric and magnetic field perpendicular to each other.

For this question of ours, the wave is moving in the eastward direction with the electric field upward (north), the magnetic field must be perpendicular at all time to the electric field in the direction of the motion of the electromagnetic wave.

Hence, the magnetic field is due east

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Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.57 A out of the jun
AlekseyPX

Answer:

a. 1.56 × 10¹⁸ electrons per second

b. The electrons in wire 3 flow into the junction.

Explanation:

Here is the complete question

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire 3? (b) In which direction do the electrons move in wire 3 -- into or out of the junction?

Solution

(a) How many electrons per second move past a point in wire 3?

Using Kirchhoff's current law, at the junction, i₁ + i₂ + i₃ = 0 where i₁ = current in wire 1 = 0.40 A, i₂ = current in wire 2 = 0.65 A and  i₃ = = current in wire 3,

So, i₃ = -(i₁ + i₂)

taking current flowing into the junction as positive and those leaving as negative, i₁ = + 0.40 A and i₂ = -0.65 A

So, i₃ = -(i₁ + i₂)

i₃ = -(0.40 A + (-0.65 A))

i₃ = -(0.40 A - 0.65 A)

i₃ = -(-0.25 A)

i₃ = 0.25 A

Since i₃ = 0.25 C/s and we have e = 1.602 × 10⁻¹⁹ C per electron, then the number of electrons flowing in wire 3 per second is i₃/e = 0.25 C/s ÷ 1.602 × 10⁻¹⁹ C per electron = 0.1561  × 10¹⁹ electrons per second = 1.561  × 10¹⁸ electrons per second ≅ 1.56 × 10¹⁸ electrons per second

(b) In which direction do the electrons move -- into or out of the junction?

Given that i₃ = + 0.25 A and that positive flows into the junction, thus, the electrons in wire 3 flow into the junction.

8 0
3 years ago
Two cars are travelling side by side down a straight road in the same direction. Both cars are travelling at a speed of 22m/s. W
ivann1987 [24]

Answer:

0 m/s

Explanation:

Relative speed is defined as the speed of an object with respect with another object.

In other words, it is the speed of an object as viewed from the frame of reference of another object.

When two objects are moving in the same direction, their relative velocity is given as:

V_{12} = V_1 - V_2

where V_1 = velocity of first object

V_2 = velocity of second object

In the case of the two cars, V_1 = V_2 = 22 m/s

Therefore:

V_{12} = 22 - 22 = 0 m/s

Their relative velocity is 0 m/s.

3 0
3 years ago
Read 2 more answers
A student is holding a stone at a certain height. The stone has 50 joules of potential energy and 0 joules of kinetic energy. Th
Hitman42 [59]

Answer:

d) The stone will have about 50 joules of kinetic energy and 0 joules of potential energy​ .

Explanation:

Given :

Initial Potential energy , P_i=50\ J .

Initial Kinetic energy , K_i=0\ J . ( because ball is in rest )

Now , we know , kinetic energy is maximum when an object reaches ground .

Also , potential energy is zero when an object is in ground .

We know , by conservation of energy :

Initial total energy = Final total energy

P_i+K_i=P_f+K_f\\\\50+0=0+K_f\\\\K_f=50 \ J

Therefore , option d) is correct .

6 0
3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
3 years ago
The circumference of a bicycle wheel is 2 meters. if it rotates at 1 revolution per second then its linear speed is
tester [92]
Given:
Circumference = 2 m
Angular speed,  ω = 1 rev/s = 2π radians/s

If the radius is r, then
2πr = 2 
r = 1/π m

The linear (tangential) speed is
v = rω
   = (1/π m)*(2π rad/s) = 0.5 m/s

Answer: 0.5 m/s
6 0
3 years ago
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