1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
3 years ago
9

Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

Chemistry
2 answers:
muminat3 years ago
4 0

Hello!

Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

We have the following data:

m (mass) = ? 

n (number of moles) = 5.20 moles

MM (Molar mass of C6H12) ≈ 84.2 g/mol

Now, let's find the mass, knowing that:

n = \dfrac{m}{MM}

5.20\:\:\diagup\!\!\!\!\!\!\!mol = \dfrac{m}{84.2\:g/\diagup\!\!\!\!\!\!\!mol}

m = 5.20*84.2

\boxed{\boxed{m = 437.84\:g}}\end{array}}\qquad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

Lapatulllka [165]3 years ago
4 0
Molar mass C₆H₁₂ = 84.2 g/mol

1 mole ---------- 84.2 g
5.20 moles ---- ?

Mass C₆H₁₂ = 5.20 * 84.2 / 1

Mass = 437.84 /1

= 437.84 g

hope this helps!

You might be interested in
How is thermal energy transferred between two objects that are at different temperatures?
qwelly [4]

Answer:

heat flows from the object that has more thermal more energy to the object with less thermal energy

8 0
3 years ago
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 Cm^{3}

First, find the Density of given substance.

Formula used :    

Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}

Now,put all the values in this formula, we get

Density=\frac{46.9 g}{3.5 Cm^{3} } = 13.4 g/Cm^{3}

So, we conclude that the density of given substance (13.4 g/Cm^{3}) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/Cm^{3} respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

3 0
3 years ago
Read 2 more answers
Wind power is:
12345 [234]
Answer) All of the above
7 0
2 years ago
Read 2 more answers
Explain what a chromosome is in your own words.
Alex787 [66]
It’s a structure of nucleic acids and protein that can be found in the nucleus; it carries genetic information through genes
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP!
uranmaximum [27]

your answer is b hope this helps


7 0
3 years ago
Read 2 more answers
Other questions:
  • What color does red litmus paper turn in an acid base and neutral solution?
    10·2 answers
  • How many elements are there in mint chocolate chip ice cream?
    9·1 answer
  • Which of the following compounds share electrons? NaCl CO CsF KBr
    8·1 answer
  • The number of unique open-chain structures corresponding to the molecular formula c3h5cl is:
    12·1 answer
  • Explain whether indicator paper or a pH meter has the higher resolution
    13·1 answer
  • What is the result of adding 2.5 × 10³ and 3.5 × 10²?
    9·2 answers
  • Which of these is caused by bacteria? A) tuberculosis B) influenza C) the common cold D) chicken pox
    15·1 answer
  • How many atoms of hydrogen are in 4Ca(OH)2​
    11·1 answer
  • The mass of an object is measured in _____.
    7·2 answers
  • Hurricanes derive their energy from: Group of answer choices the latent heat of condensation. the latent heat of fusion. the lat
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!