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1 year ago

What is true about Carbon-14 and Carbon-12?

Chemistry

1 answer:

bogdanovich [222]1 year ago

6 0

Answer:

Explanation:

<u>Correct:</u> b. The mass of the Carbon-14 sample is greater than the Carbon-12 sample, but the reactivity of both samples was the same .

- C-14 has two additional neutrons, so is heavier than C-12. The chemical properties will be the same, however.

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Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could

polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

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2 years ago

Which best explains how photosynthesis is helpful to humans? It reduces the amount of harmful rays released by the sun. It incre

masya89 [10]

Answer:I believe that the answer is c

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Which type of scientist would observe the spread of a species of red fire ants

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It would be a biologist

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2 years ago

Santiago's car has an overall average speed of 25 cm/s. If he could increase his car's overall average speed by 10%, what would

Evgen [1.6K]

Given:

The overall average speed = 25 cm/s.

The overall average speed increased by 10%.

To find:

The new overall average speed.

Solution:

We have,

Overall average speed = 25 cm/s.

The overall average speed increased by 10%. So, the new average speed is

New overall average speed = Initial average speed + 10% of initial overall average speed

$\text{New overall average speed}=25+\dfrac{10}{100}\times 25$

$\text{New overall average speed}=25+2.5$

$\text{New overall average speed}=27.5$

Therefore, the new overall average speed is 27.5 cm/s.

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