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geniusboy [140]
3 years ago
6

Based on the equation, how many grams of Br2 are required to react completely with 29.2 grams of AlCl3?

Chemistry
1 answer:
goblinko [34]3 years ago
3 0

Answer:

answer is 34.996 or 35 grams

Explanation:

Br2 + AlCl3

mass 34.996 29.2

RFM 160 133.5

moles 0.2187 0.2187

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Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 Pa at a temperature of 127 C.
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Hey there!


* Converts 1750 dm³ in liters :


1 dm³ = 1 L so 1750 dm³ = 1750 liters



* Convertes 125,000 Pa in atm :


1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm


* Convertes 127ºC in K :


127 + 273.15 => 400.15 K


R = 0.082 atm.L/mol.K


Finally, it uses an equation of clapeyron :


p * V = n * R * T


1.233 * 1750 = n * 0.082 * 400.15


2157.75 = n * 32.8123


n = 2157.75 / 32.8123


n = 65.76 moles



hope this helps!



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