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Vinvika [58]
3 years ago
13

Why do we have seasons on Earth? A) As Earth goes around the Sun and Earth's axis remains pointed toward Polaris, the Northern a

nd Southern hemispheres alternately receive more and less direct sunlight. B) The tilt of Earth's axis constantly changes between 0 and 23 1/20, giving us summer when Earth is tilted more and winter when it is straight up. C) Earth's orbital distance from the Sun varies, so that it is summer when we are closer to the Sun and winter when we are farther from the Sun. D) The hemisphere that is tilted toward the Sun is closer to the Sun than the hemisphere that is tilted away.
Physics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

The correct option is: A) As Earth goes around the Sun and Earth's axis remains pointed toward Polaris, the Northern and Southern hemispheres alternately receive more and less direct sunlight.

Explanation:

Seasons on Earth are the changes in the weather caused due to the <u>titled axis of the Earth, relative to the orbital or ecliptic plane</u>, while orbiting around the Sun. The Earth's axis of rotation is<u> tilted approximately by an angle of 23.4°. </u>

This results in the change in the intensity of the sunlight received by the Earth's surface, due to which the southern and the northern hemispheres <u>experience opposite seasons.</u>

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Which describes how chemical changes are different from physical changes?
lions [1.4K]

Answer:

B. Chemical changes involve the formation of a new substance.

Explanation:

They can both release energy, both can be measured, and chemical changes can be caused by oxygen, so I believe it would be B.

6 0
4 years ago
In the Bohr model of the hydrogen atom, an electron({rm mass};m=9.1; times 10^{ - 31;}{rm kg}) orbits a proton at a distance of
max2010maxim [7]

Answer:

n=6.56×10¹⁵Hz

Explanation:

Given Data

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

To find

Revolutions per second

Solution

Let F be the force of attraction

let n  be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by

F=mω²r......................where ω=2π  n

F=m4π²n²r...............eq(i)

as the values given where

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

we have to find n from eq(i)

n²=F/(m4π²r)

n^{2} =\frac{8.2*10^{-8} }{9.11*10^{-31}* 4\pi^{2} *5.3*10^{-11}  }\\ n^{2}=4.31*10^{31}\\ n=\sqrt{4.31*10^{31}}\\ n=6.56*10^{15}Hz

8 0
3 years ago
A car with mass mc = 1490 kg is traveling west through an intersection at a magnitude of velocity of vc = 9.5 m/s when a truck o
icang [17]

Answer:

v= - 4.507 i - 2.363 j

Explanation:

 Given that

mc= 1490 kg

vc= 9.5 m/s ( - i)

mt=  1650 kg

vt = 6.4 m/s ( -j)

There is any external force so linear momentum will remain conserve.

Lets take final speed is v.

mc .vc + mt . vt = ( mc+mt) v

1490 x 9.5 ( - i) + 1650 x 6.4 ( -j) = ( 1490+1650) v

14,155 ( -i) + 10,560 ( - j) = 3140 v

v= - 4.507 i - 2.363 j

3 0
4 years ago
Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one
kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be m_{1} and m_{2} the masses of the two laboratory carts and let suppose that m_{1} > m_{2}. The expressions for each kinetic energy are, respectively:

K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2} and K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}.

After some algebraic manipulation, the following relation is constructed:

\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}

Since \frac{m_{1}}{m_{2}} > 1, then \frac{v_{2}}{v_{1}} > 1. That is to say, v_{1} < v_{2}.

The expressions for each linear momentum are, respectively:

p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1} and p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}

Since v_{1} < v_{2}, then p_{1} > p_{2}. Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

6 0
3 years ago
What is the resultant fore acting on a 500g object accelerating 5m/s2
zimovet [89]

2.5N

Explanation:

Given parameters:

Mass of object = 500g

Acceleration = 5m/s²

unknown:

Resultant force = ?

Solution:

According to Newton's second law "the net force on a body or the resultant force is the product of its mass and acceleration".

Resultant or net force = m x  a

where  m is the mass

         a is the acceleration

Now we need to convert the mass to kg

 1000g  = 1kg

 500g  = \frac{500}{1000} = 0.5kg

Therefore;

 Input the parameters:

    Force = 0.5 x 5 = 2.5N

learn more:

Newton's law brainly.com/question/11411375

#learnwithBrainly

3 0
3 years ago
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