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3 years ago

Chlorine atom

Chemistry

1 answer:

irina [24]3 years ago

8 0

Answer:

C. Decomposition of potassium permanganate(Heating)

Explanation:

The equation of the reaction is given as;

2KMnO4 -> K2MnO4 + MnO2(s) + O2(g)

Reactant = 2KMnO4

Products = K2MnO4 + MnO2(s) + O2(g)

A. Oxygen turned in to carbon dioxide

Incorrect option - Oxygen is not the reactant

B. Sulphate and lithium boiled

Incorrect option - Sulphate and lithium are not part of this reaction

C. Decomposition of potassium permanganate(Heating)

Correct option - potassium permanganate decomposed to form K2MnO4 + MnO2(s) + O2(g)

D. None of the above

Incorrect option

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Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

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We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

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To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

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3 years ago

A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti

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Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

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To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

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Thus the molarity of the malonic acid solution is 0.08335 M

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