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likoan [24]
3 years ago
15

Chlorine atom

Chemistry
1 answer:
irina [24]3 years ago
8 0

Answer:

C. Decomposition of potassium permanganate(Heating)

Explanation:

The equation of the reaction is given as;

2KMnO4 -> K2MnO4 + MnO2(s)  + O2(g)

Reactant = 2KMnO4

Products = K2MnO4 + MnO2(s)  + O2(g)

A. Oxygen turned in to carbon dioxide

Incorrect option - Oxygen is not the reactant

B. Sulphate and lithium boiled

Incorrect option -  Sulphate and lithium are not part of this reaction

C. Decomposition of potassium permanganate(Heating)

Correct option - potassium permanganate decomposed to form K2MnO4 + MnO2(s)  + O2(g)

D. None of the above

Incorrect option

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Slove this fill in blanks​
bagirrra123 [75]

Answer:

1) Heterogeneous mixture

2). homogeneous mixture

3) water is solvent and sugar is solute

4). sublimation process

3 0
3 years ago
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In the reaction MgCl2 + 2KOH Mg(OH)2+ 2KCI, if 3 moles MgCh are added to 4 moles KOH, what determines how much Mg(OH)2 is made?
gulaghasi [49]

Answer:-

KOH determines how much Mg(OH)2 is made.

2 mol of Mg(OH)2 formed

Explanation:-

The balanced equation is

MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,

From seeing the coefficients we notice

2 mol of KOH reacts with 1 mol of MgCl2

4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2

3 moles of MgCl2 was added but only 2 mol react.

So we see there is excess MgCl2 .

Hence KOH is the limiting reactant.

So KOH determines how much Mg(OH)2 is made.

We see from the balanced chemical equation,

2 mol of KOH gives 1 mol of Mg(OH)2.

4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.

7 0
4 years ago
In what area of the united states do the fewest people live​
fiasKO [112]

Answer:

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6 0
3 years ago
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An ore sample is known to contain copper sulfate pentahydrate, CuSO4•5H2O. If a 10.000 g sample of the ore loses 0.8445 g of wat
Simora [160]

Answer:

2,341g of CuSO₄.5H₂O

Explanation:

It is possible to assume all loses water comes from CuSO₄.5H₂O. Thus:

0,8445g H₂O (1mol H₂O / 18,015g) = 0,04688 moles of water.

As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:

0,04688 moles H₂O × (1 mole CuSO₄.5H₂O / 5 moles H₂O) = 9,38x10⁻³ moles of CuSO₄.5H₂O

The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:

9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =

<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.

I hope it helps!

3 0
3 years ago
Denise owns a car that runs on a mixture of gasoline and ethanol. She can buy fuels that have 85% ethanol or 25% ethanol. How mu
Hunter-Best [27]
<span>85% ethanol | 25% ethanol | 50% ethanol
x | y | 20 gal

use x and y because you don;t know how much she needs.

0.85x | 0.25y | 20(0.5)

85% is 85/100 or 0.85, and you need that much of x, same goes for the 25% and 50% mixtures so now you can make up 2 equations
1) x + y = 20 2) 0.85x + 0.25y= 10 (you get 10 when you multiply 20 by 0.5) now you can solve for x or y using substitution.
first rewrite 1) in terms of x or y: x+ y= 20 ----> y= 20 - x now you can substitute 20- x for y in the second equation.. 0.85x + 0.25y= 10 0.85x + 0.25(20-x)= 10 distribute here..(0.25 * 20 and 0.25 * (-x) ) 0.85x + 5 - 0.25x = 10 combine like terms 0.6x +5 = 10 move the 5 over to the other side 0.6x= 10 -5 0.6x = 5 divide both sides by 0.6 x= 25/3 or 8.3 now you know the amount of x so you can substitue this back into the first equation to find y. 0.85x + 0.25y= 10 0.85(25/3) +0.25y= 10 85/12 + 0.25y= 10 0.25y = 10- 85/12 0.25y= 35/12 y= 35/3 or 11.6 you can check by putting these values into the euations: 1) x+ y= 20 25/3 + 35/3 =20 20= 20 good so far 2) 0.85x + 0.25y= 10 0.85(25/3) + 0.25(35/3)=10 10 = 10

so our values for x and y work
x= 25/3 and y= 35/3</span>
5 0
3 years ago
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