1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brilliant_brown [7]
3 years ago
10

PLEASE HELP

Chemistry
2 answers:
Crank3 years ago
8 0

Answer:

3.94 x 10⁵ pascals

Explanation:

combined gas law problem

P₁V₁/T₁ =  P₂V₂/T₂ => P₂ = P₁(V₂/V₁)(T₁2T₁)

P₁ = 1 atm at STP       P₂ = unknown

V₁ = 700 ml               V₂ = 200 ml

T₁ = 0°C = 273K        T₂ = 30°C = 303K

P₂ =  1atm(700ml/200ml)(303K/273K) = 3.89 atm

3.89 atm = 3.89 atm(1.01 x 10⁵Pa/atm) = 3.94 x 10⁵ pascals

otez555 [7]3 years ago
5 0

Answer:

P2≈393.609Kpa so I think the answer is 394 kPa

Explanation:

PV=mRT Ideal Gas Law

m and R are constant because they dont change for the problem. That means

PV/T=mR = constant

so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.

So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)

P2 = 393609 Pa

You might be interested in
Question 116 g of sunflower oil is
Luba_88 [7]
<h2>Answer:  125.41 mL</h2>

Explanation:

Volume = mass ÷ density

             =  116 g  ÷  0.925 g/mL

             =  125.41 mL

<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>
7 0
3 years ago
What is the molarity of 0.26 mol of H2SO4 dissolved in 0.3 L of solution? *
irina1246 [14]

Answer:

A

Explanation:

molarity=moles of solute/liter of solution

molarity=0.26/0.3

molarity=0.87molar

7 0
3 years ago
Find the number of moles of water that can be formed if you have 138 mol of hydrogen gas and 64 mol of oxygen gas.
charle [14.2K]
2H₂₍g₎ + O₂ ₍g₎→ 2H₂O

138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O

128 mol H₂O
6 0
4 years ago
Read 2 more answers
Select the compound that is most likely to increase the solubility of ZnSe when added to water.NaCnMgBr2NaClKClO4
vlada-n [284]

Answer:

NaCl.

Explanation:

In the solution, ZnSe ionizes to Zn^2^+ and Se^2^- . Following reaction represents the ionization of ZnSe in solution -

ZnSe ⇄ Zn^2^+ + Se^2^-

As we want to increase the solubility of ZnSe, we must decrease the concentration of dissociated ions so that the reaction continues to forward direction.

If we add NaCl to this solution, then we have Na^+ and Cl^- in the solution which will be formed by the ionization of NaCl.

Now, Zn^2^+ in the solution will react with two Cl^- ions to form ZnCl_2 as follows -

Zn^2^++2Cl^- ⇄ ZnCl_2

Due to this reaction the concentration of Zn^2^+ will decrease in the solution and more ZnSe can be soluble in the solution.

6 0
3 years ago
The first order reaction A → B, has k = 2.10. If the initial concentration of reactant A is 1.500 M, how long will it take [A] =
Semenov [28]

Answer:

ln( \binom{at}{ao}{}  )  =  - kt

Explanation:

ln( \binom{0.6}{1.5} )  =  - 2.1t

ln(0.4)  =  - 2.1t

T = 0.436.

I used the formula for first order reaction.

I hope you get this.

6 0
3 years ago
Other questions:
  • Review Part B Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nit
    5·1 answer
  • 11 Which compound has the greatest percent composition by mass of sulfur?(1) BaS (3) MgS
    8·2 answers
  • Which phrase describes an irregular galaxy?
    8·2 answers
  • The average radius of a molecule of lysozyme, an enzyme in tears, is 1.430 *10^-3 um. What is its radius in millimeter? Enter yo
    6·2 answers
  • 2 different elements have the same number of neutrons​
    8·1 answer
  • Which best describes a compound such as sodium chloride
    5·2 answers
  • Cities are measurably hotter than the surrounding suburbs
    6·2 answers
  • (science)
    6·2 answers
  • Can cells have different types of openings?
    10·1 answer
  • Modeling Nuclear Processes Quick Check
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!