Since two identical bulbs are connected in this circuit in series combination
So here same current will flow into the circuit
So here we can say
![V = V_1 + V_2](https://tex.z-dn.net/?f=V%20%3D%20V_1%20%2B%20V_2)
![V = 3 volts](https://tex.z-dn.net/?f=V%20%3D%203%20volts)
also we know that
![V_1 = iR_1](https://tex.z-dn.net/?f=V_1%20%3D%20iR_1)
![V_2 = iR_2](https://tex.z-dn.net/?f=V_2%20%3D%20iR_2)
also it is given that bulbs are identical so we have
![V_1 = V_2](https://tex.z-dn.net/?f=V_1%20%3D%20V_2)
as we have
![R_1 = R_2](https://tex.z-dn.net/?f=R_1%20%3D%20R_2)
so now we can say
![V = 2V_{CD}](https://tex.z-dn.net/?f=V%20%3D%202V_%7BCD%7D)
![3 = 2V_{CD}](https://tex.z-dn.net/?f=3%20%3D%202V_%7BCD%7D)
![V_{CD} = 1.5 Volts](https://tex.z-dn.net/?f=V_%7BCD%7D%20%3D%201.5%20Volts)
so here voltage across C and D is 1.5 volts
Answer:
<h3><u>5</u><u>4</u><u>m</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u></h3>
It decreased it because the velocity is sjsjdjdjdjdjdjdjdjdjdjfjfjfjfjdjrfkrorkd
Answer:
3200 is the answer have a good day
Explanation:
hope this helps? :))
Answer:
3ohms
Explanation:
From Ohm's Law
V = IR
V is that voltage = 3volts
I = current = 1amp
R = resistance in ohms
Putting those values into the above formula.
3volts = 1amp×R
Making R the subject
R = 3/1
R = 3ohms
The resistance of the light bulb is 3ohms.