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Capacitor in series with a 100Ω resistor and a 18.0 mH inductor will give a **resonance frequency **of 1000 Hz is **1.38F**

**Resonance Frequency **of a combination of Series LCR circuit is the frequency at which resonance is achieved in a circuit.

Resonance Frequency of a combination of Series LCR circuit is given by:

f = 1 / 2π

where, f is the resonance Resonance Frequency of a combination of Series LCR circuit

L is the Inductance of the inductor

C is the capacitance of the capacitor

Given,

f = 1000Hz

L = 18.0 mH = 0.018H

R = 100Ω

C = ?

On substituting the values in the above-mentioned formula:

1000 = 1 / 2π

2π = 0.001

On solving, C = 1.38 F

Hence, the capacitance of the given capacitor is **1.38F**.

Learn more about **Resonant frequency** here, brainly.com/question/13040523

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**Answer:**

Let N0 be the initial atoms of Be11

N0 / 2^1 = N0 / 2 Number of Be11 after 1 half-life

N0 / 2^2 = N0/ 4 Number of Be11 after 2 half-lives

30/13.81 = 2.17 half lives

N0 / 2^2.17 = N0 / 4.51 = .222 N0 or 22.2 % of atoms remain