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Helga [31]
3 years ago
7

Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)

Chemistry
1 answer:
allsm [11]3 years ago
6 0

Answer:

\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}

Explanation:

1. Density from mass and volume

\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}

2. Volume from density and mass

V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}

3. Mass from density and volume

\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}

4. Density by displacement

Volume of water + object = 24.6 mL

Volume of water                =<u> 12.8 mL</u>

Volume of object               = 11.8 mL

\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

 

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Notice that your solution has a volume of 100.0 mL. Since

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you can say that your solution has a volume that is equivalent to 110th of 1 L. Therefore, the number of moles that will be present in your sample will represent 110th of the number of moles present in 1 L of this solution.

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So, if this is how many moles you have in 100.0 mL of this solution, it follows that 1 L will contain

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You get 0.2921 moles of sucrose, you solute, per liter of solution, which means that the solution's molarity will be

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Answer link

4 0
2 years ago
The amount of space a material occupies is its
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Answer:

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Explanation:

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Explanation:

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