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Margarita [4]
3 years ago
7

If a negative charge is released in a uniform electric field move

Physics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

Explanation:

Let the electric field strength is E and the charge is q. The force experienced by the charge due to the presence of electric field is

F = q x E

The direction of force is same as that of the electric field strength if the charge is positive in nature and if the charge is negative in nature the direction of force is opposite to the direction of electric field.

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Answer: protons , neutrons and electrons
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The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li
jenyasd209 [6]

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

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3 years ago
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Jackson is designing a new heater, and he wants to experiment with different thermally conductive materials. Which of these mate
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Answer:

metal

Explanation:

metal is an excellent conductor for heat and electricity therefore making it perfect to experiment with different temperatures.

7 0
3 years ago
Whats the difference between kinetic and potential energy?
damaskus [11]
Kinetic energy is energy in motion and potential energy is stored energy
5 0
3 years ago
A block of aluminum at a temperature of T1 = 32 degrees C has a mass of m1 = 12 kg. It is brought into contact with another bloc
Mariulka [41]

Answer:T=21.33 ^{\circ}

Explanation:

Given

mass of First Block m_1=12 kg

Temperature T_1=32^{\circ}

mass of second block m_2=0.5 m_1=6 kg

Temperature T_2=9^{\circ}

Heat capacity of aluminium c=899 J/kg-K

Final Temperature acquired by both blocks at steady state

Heat loss first block =Heat gain by second block

m_1\times c\times (32-T)=m_2\times c\times (T-9)

12\times 899\times (32-T)=6\times 899\times (T-9)

2\times 32=3T

T=\frac{64}{3}=21.33 ^{\circ}

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3 years ago
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