A 1.40-kg ball tied to a string fixed to the ceiling is pulled to one side by a force F→ . where L = 1.40 kg. What is the tensio
1 answer:
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Answer:
SKID
Explanation:
In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.
Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.
Y axis y
N- W = 0
N = W
X axis (radial)
fr = m a
the acceleration in the curve is centripetal
a =
the friction force has the expression
fr = μ N
we substitute
μ mg = m v²/r
v =
we calculate
v =
v = 1,715 m / s
to compare with the cyclist's speed let's reduce to the SI system
v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s
We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID
Answer:
A.
B.s=397.6 m
Explanation:
Given that
speed u= 284.4 m/s
time t = 1.4 s
here he want to reduce the velocity from 284.4 m/s to 0 m/s.
So the final speed v= 0 m/s
We know that
v= u + at
So now by putting the values
0 = 284.4 -a x 1.4 (here we take negative sign because this is the case of de acceleration)
So the acceleration while stopping will be .
Lets take distance travel before come top rest is s
We know that
s=397.6 m
So the distance travel while stopping is 397.6 m.