Question

A 1.40-kg ball tied to a string fixed to the ceiling is pulled to one side by a force F→ . where L = 1.40 kg. What is the tension in the string just before the ball is released and allowed to swing back and forth?

Answer 1

Answer:

T=13.72N

Explanation:

The tension before the ball is released have no angle is in rest at the same axis of the weight so:

∑F=0

Using Newton law in this case the ball is tied so tension before become to swing is

∑F=FN-T=0

$T=F_{N}$

$T=m*g$

$T=1.40Kg*9.8\frac{m}{s^2}$

$T=13.72N$