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3 years ago

Why do rocks on the ocean floor form a patter of magnetized strpes?

Physics

2 answers:

Citrus2011 [14]3 years ago

8 0

Answer:

The sea-floor spreading starts when the magma rises and erupts from the cracks along the mid-ocean ridges. Once the molten material solidifies, the older rock gets pushed away from the ridge and the new rock forms in the centre of the mid-ocean ridge. According to scientists, the Earth’s magnetic field is involved in this process. Since the oceanic crust contains iron, the way the rocks on the ocean floor hardened on both sides of the mid-ocean ridges are influenced by the direction of the magnetic field. As a result, it forms a pattern that resembles stripes that are alternately pointed north and south.

Or if you want a small answer:

The rock of the ocean floor contains iron. As molten material cools and hardens, the iron particles inside lines up in the direction of Earth's magnetic poles, creating a pattern of magnetized stripes.

DENIUS [597]3 years ago

4 0

Answer:

The striped magnetic pattern develops because, as the oceanic crust pulls apart, magma rises to the surface at mid-ocean ridges and spills out to create new bands of the ocean floor.

Explanation:

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Dmitrij [34]

Answer is C is the correct answer

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4 years ago

A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de

oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

$\eta = \frac{W}{Q_{in}}$

where

W is the useful work done by the engine

$Q_{in}$ is the heat in input to the machine

In this problem, we have:

$Q_{in}=600 kJ$ is the heat absorbed

$W=600 kJ-175 kJ=425 kJ$ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

$\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%$

(a) $737^{\circ}C$

The efficiency of an engine can also be rewritten as

$\eta = 1-\frac{T_C}{T_H}$

where

$T_C$ is the absolute temperature of the cold sink

$T_H$ is the temperature of the source

In this problem, the temperature of the sink is

$T_C = 20^{\circ}C + 273=293 K$

So we can re-arrange the equation to find the temperature of the source:

$T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C$

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3 years ago

A uniform 1.4-kg rod that is 0.75 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both

svetlana [45]

Answer:

7 deg

Explanation:

$m$ = mass of the rod = $1.4 kg$

$W$ = weight of the rod = $mg = (1.4) (9.8) = 13.72 N$

$k_{L}$ = spring constant for left spring = $59 Nm^{-1}$

$k_{R}$ = spring constant for right spring = $33 Nm^{-1}$

$x_{L}$ = stretch in the left spring

$x_{R}$ = stretch in the right spring

$L$ = length of the rod = 0.75 m

$\theta$ = Angle the rod makes with the horizontal

Using equilibrium of force in vertical direction for left spring

$k_{L} x_{L} = (0.5) W\\(59) x_{L} = (0.5) (13.72)\\x_{L} = 0.116 m$

Using equilibrium of force in vertical direction for right spring

$k_{R} x_{R} = (0.5) W\\(33) x_{R} = (0.5) (13.72)\\x_{R} = 0.208 m$

Angle made with the horizontal is given as

$\theta = tan^{-1}(\frac{(x_{R} - x_{L})}{L} )\\\theta = tan^{-1}(\frac{(0.208 - 0.116)}{0.75} )\\\theta = 7 deg$

3 0

4 years ago

Molecules made up of atoms of the same element are ________________ because the atoms are identical. So they share electrons equ

igomit [66]

Nonpolar is the answer

6 0

3 years ago

The velocity of a particle moving along the x axis is given by vx = a t − b t3 for t > 0 , where a = 27 m/s 2 , b = 3.1 m/s 4

Elanso [62]

Answer:

-54 m/s²

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,

Acceleration A = change in velocity/time

A = dv/dt

Given Vx = at − bt³

The time at which the particle reaches its maximum displacement is at when vx = 0.

0 = at-bt³

t(a-bt²) = 0

a-bt² = 0

a = bt²

t² = a/b ... (1)

A = dvx/dt = a - 3bt²(by differentiating)

Acceleration = a - 3bt²... (2)

Substituting t² = a/b into equation 2 will give;

Acceleration = a - 3b(a/b)

Acceleration = a-3a

Acceleration = -2a

Substituting the value of a = 27m/s into the resulting equation of acceleration gives;

Acceleration = -2(27)

Acceleration = -54m/s²

Therefore at maximum displacement in the positive x direction, the acceleration of the particle will be -54m/s²

4 0

4 years ago