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MaRussiya [10]
3 years ago
7

Why do rocks on the ocean floor form a patter of magnetized strpes?

Physics
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

The sea-floor spreading starts when the magma rises and erupts from the cracks along the mid-ocean ridges. Once the molten material solidifies, the older rock gets pushed away from the ridge and the new rock forms in the centre of the mid-ocean ridge. According to scientists, the Earth’s magnetic field is involved in this process. Since the oceanic crust contains iron, the way the rocks on the ocean floor hardened on both sides of the mid-ocean ridges are influenced by the direction of the magnetic field. As a result, it forms a pattern that resembles stripes that are alternately pointed north and south.

Or if you want a small answer:

The rock of the ocean floor contains iron. As molten material cools and hardens, the iron particles inside lines up in the direction of Earth's magnetic poles, creating a pattern of magnetized stripes.

DENIUS [597]3 years ago
4 0

Answer:

The striped magnetic pattern develops because, as the oceanic crust pulls apart, magma rises to the surface at mid-ocean ridges and spills out to create new bands of the ocean floor.

Explanation:

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A monatomic ideal gas undergoes an adiabatic expansion to double its volume. the same final state can be reached by an isobaric
Vlada [557]
(2^(1-γ)-1)/(1-γ) where γ is the heat capacity ratio, Cp/Cv. See attached image for the working.

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5 0
3 years ago
A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?
irakobra [83]

Answer:

New volume, v2 = 0.8L

Explanation:

<u>Given the following data;</u>

Original Volume = 2L

Original Temperature = 280K

New Temperature = 700K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

VT = K

\frac{V1}{T1} = \frac{V2}{T2}

\frac{V1}{T1} = \frac{V2}{T2}

Making V2 as the subject formula, we have;

V_{2}= \frac{V1}{T1} * T_{2}

V_{2}= \frac{2}{700} * 280

V_{2}= 0.0029 * 280

V2 = 0.8L

Therefore, the volume of the gas after it is heated is 0.8L.

7 0
3 years ago
In which of the two situations described is more energy transferred?
Furkat [3]

Answer:

More energy is transferred in situation A

Explanation:

Each of the situations are analyzed as follows;

Situation A

The temperature of the cup of hot chocolate = 40 °C

The temperature of the interior of the freezer in which the chocolate is placed = -20 °C

We note that at 0°C, the water in the chocolate freezes

The energy transferred by the chocolate to the freezer before freezing is given approximately as follows;

E₁ = m×c₁×ΔT₁

Where;

m = The mass of the chocolate

c₁ = The specific heat capacity of water = 4.184 kJ/(kg·K)

ΔT₁ = The change in temperature from 40 °C to 0°C

Therefore, we have;

E₁ = m×4.184×(40 - 0) = 167.360·m kJ

The heat the coffee gives to turn to ice is given as follows;

E₂ = m·H_f

Where;

H_f = The latent heat of fusion = 334 kJ/kg

∴ E₂ = m × 334 kJ/kg = 334·m kJ

The heat required to cool the frozen ice to -20 °C is given as follows;

E₃ = m·c₂·ΔT₂

Where;

c₂ = The specific heat capacity of ice = 2.108 kJ/(kg·K)

Therefore, we have;

E₃ = m × 2.108 ×(0 - (-20)) = 42.16

E₃ = 42.16·m kJ/(kg·K)

The total heat transferred = (167.360 + 334 + 42.16)·m kJ/(kg·K) = 543.52·m kJ/(kg·K)

Situation B

The temperature of the cup of hot chocolate = 90 °C

The temperature of the room in which the chocolate is placed = 25 °C

The heat transferred by the hot cup of coffee, E, is given as follows;

E = m×4.184×(90 - 25) = 271.96

∴ E = 271.96 kJ/(kg·K)

Therefore, the total heat transferred in situation A is approximately twice the heat transferred in situation B and is therefore more than the heat transferred in situation B

Energy transferred in situation A = 543.52 kJ/(kg·K)

Energy transferred in situation B = 271.96 kJ/(kg·K)

Energy transferred in situation A ≈ 2 × Energy transferred in situation B

∴ Energy transferred in situation A > Energy transferred in situation B.

3 0
3 years ago
A 6 cm object is 15 cm from a convex lens that has a focal length of 5 cm. What is the distance of the image from the lens, to t
Vesna [10]

Answer:

7.50 cm

Explanation:

The formula

1/v + 1/u = 1/f

Is used.

where.

u is the object distance.

v is the image distance.

f is the focal length of the lens.

1/v + 1/15 = 1/5

1/v = 1/5 - 1/15

1/v = (3-1)/15

1/v = 2/15

2v = 15

V = 15/2

V = 7.5 cm

For focal length, f in lens is always taken as negative for concave and positive for convex. ... And for image distance, V in lens it is taken as positive in Convex lens since image is formed on +X side. It is taken as negative in Concave lens since image is formed in -X side of the Cartesian.

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3 years ago
Rephrase the law of universal gravitation
IRISSAK [1]
The law of universal gravitation says that one object attracts every other object using a proportional force to the mass of the object.
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