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Yuliya22 [10]
3 years ago
13

The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4 -2.

Chemistry
1 answer:
suter [353]3 years ago
6 0

Answer:

The balanced equations for those dissociations are:

Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻ (aq)

H₂SO₄ (aq) → 2H⁺(aq) + SO₄⁻²(aq)

Explanation:

As a strong base, the barium hidroxide gives OH⁻ to the solution

As a strong acid, the sulfuric acid gives H⁺ to the solution

Ba(OH)₂, is a strong base so the dissociation is complete.

H₂SO₄ is considerd a strong acid, but only the first deprotonation is strong.

The second proton that is released, has a weak dissociation.

H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

HSO₄⁻(aq) ⇄ H⁺ (aq) + SO₄⁻² (aq)       Ka

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