The displacement ........................
v₀ = initial speed as tarzan grabs the vine = 5.3 m/s
v = final speed as the tarzan reach the maximum height = 0 m/s
h = maximum height gained by the tarzan
m = mass of tarzan
using conservation of energy
initial kinetic energy = final kinetic energy + potential energy
(0.5) m v²₀ = (0.5) m v² + m g h
(0.5) v²₀ = (0.5) v² + g h
(0.5) (5.3)² = (0.5) (0)² + (9.8) h
h = 1.43 m
From the average speed you can fix an equation:
Average speed = distance / time
You know the average speed = 65.1 kg / h, then
65.1 = distance / total time,
where total time is the time traveling plus 22.0 minutes
Call t the time treavelling and pass 22 minutes to hours:
65.1 = distance / [t + 22/60] ==> distance = [t + 22/60]*65.1
From the constant speed, you can fix a second equation
Constant speed = distance / time traveling
94.5 = distance / t ==> distance = 94.5 * t
The distance is the same in both equations, then you have:
[t +22/60] * 65.1 = 94.5 t
Now you can solve for t.
65.1t + 22*65.1/60 = 94.5t
94.5t - 65.1t = 22*65.1/60
29.4t = 23.87
t = 23.87 / 29.4
t = 0.812 hours
distance = 94.5 km/h * 0.812 h = 76.7 km
Answers: 1) 0.81 hours, 2) 76.7 km
Answer:
3500N
Explanation:
Given parameters:
Mass of driver = 50kg
Speed = 35m/s
Time = 0.5s
Unknown:
Average force the seat belt exerts on her = ?
Solution:
The average force the seat belt exerts on her can be deduced from Newton's second law of motion.
F = mass x acceleration
So;
F = mass x 
F = 50 x 
= 3500N
