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Lisa [10]
3 years ago
8

A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressu

re of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?
Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer : The moles of oxygen gas lost are 2.88 mole

Explanation :

According to the Avogadro's Law, the volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of oxygen gas = 12.6 L

V_2 = final volume of oxygen gas = 12.1 L

n_1 = initial moles of oxygen gas = 3.0 mole

n_2 = final moles of oxygen gas = ?

Now put all the given values in the above formula, we get the final moles of oxygen gas.

\frac{12.6L}{12.1L}=\frac{3.0mole}{n_2}

n_2=2.88mole

Therefore, the moles of oxygen gas lost are 2.88 mole

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