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Sedaia [141]
4 years ago
14

Common static electricity involves charges ranging from nanocoulombs to microcoulombs. (a) How many electrons are needed to form

a charge of –2.00nC (b) How many electrons must be removed from a neutral object to leave a net charge of 0.500µC ?
Physics
1 answer:
Gnoma [55]4 years ago
8 0

Answer:

a) 1.24*10¹⁰ . b) 3.11*10¹²

Explanation:

The charge is quantized, so any charge is a multiple of the elementary charge e, which is the charge of one electron (being negative) or a proton (if it is positive).

The value of e is 1.61*10⁻¹⁹ coulombs.

a) So, if we need to form a charge of -2.00 nC, this will be equal to the following expression:

Q = -2.00 nC = n*e = n*(-1.61*10⁻¹⁹) C

Solving for n, replacing nC by 10⁻⁹ C, we have:

n=- 2*10⁻9 C /- 1.61.10⁻¹⁹ C = 1.24*10¹⁰ electrons.

b) In the same way, we get the number of electrons (as a negative charge) that it is needed to remove from a neutral object to leave a net charge of 0.500 μC = 5*10⁻⁷ C, as follows:

n = -5*10⁻⁷ C / -1.61*10⁻¹⁹ C =3.11*10¹² electrons.

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Answer:

radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

Explanation:

Electromagnetic waves are the waves which are created as the result of the electrical waves which are perpendicular to each other and also perpendicular to the direction of propagation.

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In order of the increasing frequency and the photon energy and the decreasing wavelength the spectrum are:  

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3 years ago
A sports car moving at constant speed travels 164 m in 13.77 s. If it then brakes and comes to a stop in 3.6 s. What is its acce
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Answer:

a = - 0.3376 g's

Explanation:

The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s

It brakes and now comes to a stop in 3.6 s.

Thus final velocity = 0 m/s

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In terms of g's", where 1.00 g = 9.80 m/s², we have;

a = -3.308/9.8 g's

a = - 0.3376 g's

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