The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
(800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
V2 = 34.1 mL
Answer:
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Explanation:
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Boiling point elevation is given as:
ΔTb=iKbm
Where,
ΔTb=elevation in the boiling point
that is given by expression:
ΔTb=Tb (solution) - Tb (pure solvent)
Here Tb (pure solvent)=118.1 °C
i for CaCO3= 2
Kb=2.93 °C/m
m=Molality of CaCO₃:
Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)
=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)
=(100.0÷100 g/mol)/0.4
= 2.5 m
So now putting value of m, i and Kb in the boiling point elevation equation we get:
ΔTb=iKbm
=2×2.93×2.5
=14.65 °C
boiling point of a solution can be calculated:
ΔTb=Tb (solution) - Tb (pure solvent)
14.65=Tb (solution)-118.1
Tb (solution)=118.1+14.65
=132.75
The prescription in mg/Kg of body weight is 5.62 mg/kg.
<h3>How to convert to mg required per kg of body weight?</h3>
Drugs are chemicals that are taken into the body and they are able to help to correct anomalies in the bodies. Drugs are taken according to the kind of ailment that a person is suffering from.
The nature of the drug and the severity of thee ailment of the person determines the dose of the drug.
Now we know that;
1 g/pound =2204.6244 mg/kg
0.00255g/lb = 0.00255g/lb * 2204.6244 mg/kg/1 g/pound
= 5.62 mg/kg
Learn more about unit conversion:brainly.com/question/4736731
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Missing parts;
A prescription medication requires 0.00255 g per lb of body weight. Convert this quantity to the number of mg required per kg of body weight.
