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Masja [62]
3 years ago
8

86 Km/h convertir a (m/min)

Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer: 1433.3 m/min

Explanation:

For 86 Km/h converted to a (m/min), convert kilometers to meters, and hour to minutes

So, 86 Km/h means 86 kilometers per 1 hour

- If 1 kilometer = 1000 metres

86 kilometers = 86 x 1000 = 86,000m

- If 1 hour = 60 minute

1 hour = 60 minutes

In m/min: (86,000m / 60 minute)

= 1433.3 m/min

Thus, 86 Km/h convert to 1433.3 m/min

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I’d say B is the best choice

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3 years ago
A spring has K=24 N/m, we put in its end an object with 4 kg, if we pull the object 0.5 m then leave it, what would be the speed
adoni [48]

Answer:

Velocity- v=10m/s south Speed- v=10m/s  

Explanation:

the salar measurement of how fast an object is moving.

Velocity- v=10m/s south :

The vector rate of change of position.

Speed- v=10 m/s   :  the salar measurement of how fast an object is moving.

8 0
2 years ago
If the temperature of a gas is increased by 10x, what will happen to the volume?
xxMikexx [17]

The volume of a gas will increase by ten times if the temperature is increased by ten times.

<h3>Relationship between the volume of a gas and temperature</h3>

The relationship between the volume of a gas and its temperature is explained in Charles' law of gases which states that:

  • The volume of a fixed mass of gas is directly proportional to its temperature provided the pressure of the gas is kept constant.

This means that if the temperature of a gas is increased by any given factor, the volume increases by the same factor proportionally.

Therefore, if the volume of a gas will increase by ten times if the temperature is increased by ten times.

Learn more about gas volume and temperature at: brainly.com/question/18706379

8 0
3 years ago
A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on
muminat

Answer:

66.02m/s

Explanation:

the equation describing the distance covered in the horizontal direction is

x=ucos\alpha t-(1/2)gt^{2} but the acceleration in the horizontal path is zero, hence we have

x=ucos\alpha t

Since the horizontal distance covered is 155m at 7.6secs, we have ucos\alpha =\frac{155}{7.6} \\ucos\alpha =20.38.............equation 1

Also from the vertical path, the distance covered is expressed as

y=usin\alpha t-(1/2)gt^{2}

since the horizontal distance covered in 7.6secs is 195m, then we have

y=usin\alpha t-(1/2)gt^{2}\\y=7.6usin\alpha -4.9(7.6)^{2}\\478.02=7.6usin\alpha \\usin\alpha =62.9...........equation 2

Hence if we divide both equation 1 and 2 we arrive at

\frac{usin\alpha }{ucos\alpha } =\frac{62.9}{20.38} \\tan\alpha =3.08\\\alpha =tan^{-1}(3.08)\\\alpha =72.02^{0}\\

Hence if we substitute the angle into the equation 1 we have

ucos72.02=20.38\\u=66.02m/s

Hence the initial velocity is 66.02m/s

3 0
4 years ago
A plane flies from base camp to lake a, 205 km away in the direction 20.0° north of east. after dropping off supplies it flies
miss Akunina [59]
Draw a diagram to illustrate the problem as shown in the figure below.

Camp A  is 20° north of east from the camp, therefore
m∠CAB = 80°
where C => base camp.

Let d = distance from lake B to the base camp, at x° west of south.
Apply the Law of Cosines to determine d.
d² = 205² + 175² - 2*205*175*cos80⁰
     = 6.0191 x 10⁴
d = 245.338 km

Apply the Law of Sines to obtain
\frac{sin(x+30)}{205}= \frac{sin80^{o}}{245.338}\\ \\ sin(x+30)=( \frac{205}{245.338})sin80^{o}=   0.8229
x+30 = sin⁻¹ 0.8229 = 55.4°
x = 25.4°

Answer:
The distance from lake B to base camp is 243.3km (nearest tenth).
The direction is 25.4° west of south.

7 0
3 years ago
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