All categories

3 years ago

86 Km/h convertir a (m/min)

Physics

1 answer:

gogolik [260]3 years ago

5 0

Answer: 1433.3 m/min

Explanation:

For 86 Km/h converted to a (m/min), convert kilometers to meters, and hour to minutes

So, 86 Km/h means 86 kilometers per 1 hour

- If 1 kilometer = 1000 metres

86 kilometers = 86 x 1000 = 86,000m

- If 1 hour = 60 minute

1 hour = 60 minutes

In m/min: (86,000m / 60 minute)

= 1433.3 m/min

Thus, 86 Km/h convert to 1433.3 m/min

You might be interested in

The record time for a Tour de France cyclist to ascend the 1100-m-high Alpe d'Huez is 37.5 min. The rider and his bike had a mas

Leni [432]

Answer

given,

height of Alpe d'Huez = 1100-m

time = 37.5 min

mass of the rider and his bike = 65 Kg

the metabolic power to ride = 700 W

U = m g y

U = 65 x 9.8 x 1100

U = 700700 J

since efficiency is 25%

$E_{chem} = \dfrac{U}{e}$

$E_{chem} = \dfrac{700700}{0.25}$

$E_{chem} = 2802800$

$E_{chem} = \dfrac{2802800}{4.19 \time 10^3}$

$E_{chem} =668.9\ cal$

b) $P = \dfrac{E_{chem}}{t}$

$P = \dfrac{2802800}{37.5\times 60\ s}$

P = 1245.68 W

8 0

3 years ago

Read 2 more answers

What metal is used to make hard magnets?

Lelu [443]

The most common metals used for permanent magnets are iron, nickel, cobalt and some alloys of rare earth metals

3 0

4 years ago

Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at

amid [387]

"The path difference between the two waves should be one-quarter of a wavelength" is the statement among the choices given in the question that describes the <span>path difference between the two waves. The correct option among all the options that are given in the question is the fifth statement or the penultimate statement.</span>

3 0

4 years ago

A brass rod with a length of 1.22 m and a cross-sectional area of 2.19 cm2 is fastened end to end to a nickel rod with length L

GaryK [48]

Answer:

a) L₂ = 0.676 m

b) σ₁ = 2.28*10⁸ N/m²

σ₂ = 9.62*10⁸ N/m²

c) ε₁ = 0.00253678

ε₂ = 0.00457875

Explanation:

Given info

L₁ = 1.22 m

A₁ = 2.19 cm² = 2.19*10⁻⁴ m²

L₂ = ?

A₂ = 0.52 cm² = 0.52*10⁻⁴ m²

P = 5.00*10⁴ N

E₁ = 9*10¹⁰ N/m²

E₂ = 2.1*10¹¹ N/m²

In order to get the length L of the nickel rod if the elongations of the two rods are equal, we can say that

ΔL₁ = ΔL₂ ⇒ P*L₁/(A₁*E₁) = P*L₂/(A₂*E₂)

⇒ L₂ = A₂*E₂*L₁ / (A₁*E₁)

⇒ L₂ = (0.52*10⁻⁴ m²)*(2.1*10¹¹ N/m²)*(1.22 m) / (2.19*10⁻⁴ m²*9*10¹⁰ N/m²)

⇒ L₂ = 0.676 m

The stress in the brass rod is obtained as follows

σ₁ = P/A₁ ⇒ σ = 5.00*10⁴ N / 2.19*10⁻⁴ m² = 2.28*10⁸ N/m²

The stress in the niquel rod is obtained as follows

σ₂ = P/A₂ ⇒ σ = 5.00*10⁴ N / 0.52*10⁻⁴ m² = 9.62*10⁸ N/m²

The strain in the brass rod is obtained as follows

σ₁ = E₁*ε₁ ⇒ ε₁ = σ₁ / E₁

⇒ ε₁ = 2.28*10⁸ N/m² / 9*10¹⁰ N/m² = 0.00253678

The strain in the niquel rod is obtained as follows

σ₂ = E₂*ε₂ ⇒ ε₂ = σ₂ / E₂

⇒ ε₂ = 9.62*10⁸ N/m² / 2.1*10¹¹ N/m² = 0.00457875

3 0

3 years ago

Tommy was walking at a rate of 4 miles hour at noon and at 12:30 pm he was walking at a brisk rate of 6 miles hour . Two hours l

maks197457 [2]

Answer:

B) Tommy had a positive acceleration between noon and 12:30 pm.

Explanation:

Acceleration is defined as the rate of change of velocity:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time

In the problem,

- At noon, Tommy is walking at a velocity of 4 mi/h

- At 12.30 pm, Tommy is walking at a velocity of 6 mi/h

- A time of half an hour (0.5 h) passed between the two moments

So Tommy's acceleration is

$a=\frac{6 mi/h-4 mi/h}{0.5 h}=4 mi/h^2$

and the acceleration is positive, since the velocity has increased.

3 0

3 years ago

Read 2 more answers