The first one is B
and the second one is A hope this helps
Answer:
(D)
Explanation:
A(2,3,4,6,8)
B(6,9,12,15,18)
(AuB)=(2,3,4,6,8,9,12,15,18)
Answer:
T2 = 662°c Q(in) = 911kj W(out) = 180kj
Explanation:
1. Firstly, we find the mass from the initial volume and specific volume from steam table A-5 for given pressure and state.
M = V(1)/a(1) = 0.6/0.7183(kg)
Where a(1) = specific volume
M = 0.835kg
The work is determined from the final pressure and the volume change that occurs when it is reached.
W = P2(V2 - V1)
W = P2V2
= 300×0.6kg = 180kg
Therefore, to get the final temperature and final pressure, the final temperature is determined fro steam table A-6 using interpolation.
T2 = T1* + T2*-T1*/a2*-a1* (a2-a1*)
T2 = 600 + 700-600/1.4958-1.34139 (1.43746-1.34139)
T2 = 662°c
2. The final internal energy can be determined in the same way just like the initial ones were done. From A-5 on steam table given the pressure
The heat Q(in) = ∆u + W(out)
= m(U2-U1) + W(out)
= 0.835(3412.3-2536.8)kj
+ 180
Q(in) = 911kj
Answer:
a) 24.918 m
b) 4.5078 seconds
c) [0.18, 0.39]
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
At the beginning of the last 1 second the velocity will be 15.095 m/s
Taking that as the final velocity of the path from the maximum height we find time
So, the ball traveled for 1+1.539 = 2.2539 seconds from the maximum height to the ground.
The maximum height the ball traveled is 24.918 m.
The time the ball will take to go up is 2.2539 seconds
So, total time the ball will be in flight is 2.2539+2.2539 = 4.5078 seconds
Solving the above equation we get
t = 0.18 seconds
Solving the equation we get
t = 0.39 seconds
So, the ball will traveling in the [0.18, 0.39] seconds of the flight
