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Virty [35]
2 years ago
6

Is quartzite a mineral, a rock, or neither?

Physics
1 answer:
Licemer1 [7]2 years ago
3 0
It’s a metamorphic rock, so for that it’s rock I also enjoy that anime
You might be interested in
A proton is accelerated down a uniform electric field of 450 N/C. Calculate the acceleration of this proton.
olasank [31]

Answer:

The acceleration of proton will be 431.137\times 10^8m/sec^2

Explanation:

We have given electric field E = 450 N/C

Charge on proton =1.6\times 10^{-19}C

Force on electron due to electric field is given by F=qE=1.6\times 10^{-19}\times 450=720\times 10^{-19}N

Mass of electron m=1.67\times 10^{-27}kg

Now according to second law of motion F=ma

So 720\times10^{-19}=1.67\times 10^{-27}a

a=431.137\times 10^8m/sec^2

So the acceleration of proton will be 431.137\times 10^8m/sec^2

6 0
4 years ago
What causes the different colors of visible light in the electromagnetic spectrum?
liraira [26]

Answer:

The color of the light is determined by the frequency of the light wave. Red, is lowest, frequency and violet is the highest.

5 0
4 years ago
A ball is projected horizontally from a table 1.0 m high and hits the ground after falling from a time t=0.45s. If the ball trav
photoshop1234 [79]

The initial velocity is 6.7 m/s

Explanation:

The motion of the ball is a projectile motion, therefore it consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

x=v_x t

where

v_x is the horizontal velocity

t is the time of flight

Here we have:

t = 0.45 s

x = 3.0 m

And so solving for v_x, we find

v_x = \frac{3.0}{0.45}=6.7 m/s

And since the ball was initially projected horizontally, this is also the initial velocity.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
In this lab you will use a cart and a track to explore Newton's second law of motion. You will vary two different variables and
Savatey [412]

<u>Answer:</u>

<em>Newtons II law: </em>

<em>     </em>It  is defined as<em> "the net force acting on the object is a product of mass and acceleration of the body"</em> . Also it defines that the <em>"acceleration of an object is dependent on net force and mass of the body".</em>

Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.

Whenever the hanging weight moves downwards, the cart will accelerate to right side.

<em>For the hanging weight/mass</em>

When hanging weight of mass is m₁ and accelerate due to gravitational force g.

           Therefore we can write F = m₁ .g

and the tension acts in upward direction T (negetive)

        Now, Fnet = m₁ .g - T

                          = m₁.a

So From Newtons II law<em> F =  m.a</em>

3 0
3 years ago
Read 2 more answers
A coil 3.85 cm radius, containing 450 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Nimfa-mama [501]

Answer:

0.025V + (0.000218V/s³) t³

Explanation:

Parameters given:

Radius of coil, r = 3.85 cm = 0.0385 m

Number of turns, N = 450

Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.

The magnitude of Induced EMF is given as:

E = N * A * dB/dt

Where A is the area of the coil

First, we differentiate the magnetic field with respect to time:

dB/dt = 0.012 + 0.000104t³

Therefore, EMF will be:

E = 450 * 3.142 * (0.012 + 0.000104t³)

E = 2.096(0.012 + 0.000104t³)

E = 0.025V + (0.000218V/s³)t³

6 0
3 years ago
Read 2 more answers
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