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3 years ago

¿Todos los solutos se disuelven en cualquier solvente?

Chemistry

1 answer:

Katen [24]3 years ago

6 0

Answer:

Explanation: No. Todos los solutos tienen una solubilidad diferente, lo que significa que todos tienen una cantidad única de gramos que se disolverían en el mismo solvente. una solución que ha disuelto todo el soluto que puede contener a una temperatura determinada.

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If 3.75 moles of aluminum react, how many moles of sulfur are needed?

aliya0001 [1]

Answer:(A) 0.70 mol

Explanation:

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2 years ago

This feature of a volcano is called an____________________which releases heated ash and Tephra through its column generating its

trapecia [35]

Answer:

Volcanic Eruption releases heated ash and Tephra through its column generating its own lightning.

Hope it helps!<3

7 0

3 years ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

<u>Answer:</u> The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

<u>Explanation:</u>

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

2 years ago

Lithium bromide dissociates in water according to the following thermochemical equation: LiBr(s) → Li+ (aq) + Br– (aq) ΔH = –48.

madreJ [45]

Answer:

Final temperature of water is $48.3^{0}\textrm{C}$

Explanation:

1 mol of LiBr releases 48.83 kJ of heat upon dissolution in water.

So, 2 moles of LiBr release $(2\times 48.83)kJ$ or 97.66 kJ of heat upon dissolution in water.

This amount of heat is consumed by 1000.0 g of water. Hence temperature of water will increase.

Let's say final temperature of water is $t^{0}\textrm{C}$ .

So, change in temperature ( $\Delta T$ ) of water is $(t-25)^{0}\textrm{C}$ or (t-25) K

Heat capacity (C) of water is $4.184\frac{J}{g.K}$

Hence, $m_{water}\times C_{water}\times \Delta T_{water}=97.66\times 10^{3}J$

where m is mass

So, $(1000.0g)\times (4.184\frac{J}{g.K})\times (t-25)K=97.66\times 10^{3}J$

or, $t=48.3$

Hence final temperature of water is $48.3^{0}\textrm{C}$

3 0

2 years ago

How can weak acids and weak bases cause pH stress to cells?

telo118 [61]

Answer:

Explanation:

If a cell has transporters that are not well regulated, weak acids or weak bases can accumulate inside the cells and cause stress.

3 0

2 years ago