¿Todos los solutos se disuelven en cualquier solvente?

Chemistry

1 answer:

Katen [24]3 years ago

6 0

Answer:

Explanation: No. Todos los solutos tienen una solubilidad diferente, lo que significa que todos tienen una cantidad única de gramos que se disolverían en el mismo solvente. una solución que ha disuelto todo el soluto que puede contener a una temperatura determinada.

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To separate a mixture of benzoic acid and fluorene, we are going to use an acid-base extraction technique. Most carboxylic acids

pentagon [3]

Answer: please find attached to see the structure.

1. THE STRUCTURE OF BENZOIC ACID AND FLUORENE, soluble in ether and insoluble in water.

2. THE STRUCTURE OF CARBOXYLIC ACID BEEN EXTRACTED.

Explanation: the mixture of benzoic acid and fluorene are the first diagrams which shows the carboxylic acid attached to the benzene ring, which are soluble in ether and insoluble in water. When dissolved in NaOH(aq) is the carboxy ion becomes soluble in water but insoluble in ether, this is seen in the second diagram.

The third diagram shows the carboxylic acid been precipitated and soluble in ether but insoluble in water.

NOTE THE TWO MAIN DIAGRAM IS THE FIRST AND THE LAST DIAGRAM, WHERE CARBOXYLIC ACID DISSOLVES IN AQUEOUS SODIUM HYDROXIDE, AND WHEN THE ACID IS BEEN PRECIPITATED IN AQUEOUS HCl.

ALSO NOTE THE CHANGE IN BENZOIC RING MIXED WITH FLUORENE TO THAT OF THE ACID BEEN EXTRACTED.

Hope together with the picture, this has helped you.

8 0

4 years ago

Why do elements that have positive ions occur on the left side of the periodic table?

HACTEHA [7]

The elements on the left side of the periodic table are positive ions because they all lose electrons to find balance, thus leaving them with a positive charge.

4 0

4 years ago

Which one of the following substances would be the most soluble in CCl4?

maria [59]

Answer: Option (d) is the correct answer.

Explanation:

Carbon tetrachloride $(CCl_{4})$ is a non-polar solvent. Whereas out of the given options, $Na_{2}SO_{4}$ , $H_{2}O$ , $CH_{3}CH_{2}CH_{2}CH_{2}OH$ , and HI are all polar molecules.