3 years ago

What is the theoretical yield of so3 produced by the quantities described in part a? express your answer numerically in grams?

1 answer:

8 0

Sulfur reacts with oxygen to yield SO3 as shown in the equation below;
2S(g)+ 3O2(g) = 2SO3(g)
From part A 7.49 g of S were used.
The atomic mass of sulfur is 32.06 g/mol
Hence, the number of moles of sulfur used
7.49 / 32.06 = 0.2336 moles
The mole ratio of S : SO3 is 1:1
Thus the mass of SO3 will be ( 1 mol of SO3= 80.06 g)
0.2336 moles × 80.06 = 18.7 g

You might be interested in

In your own words, give a summary of the history of the atom. Make sure to use names of models and the scientists associated wit

Bumek [7]

I dont know that’s a hard one I’m in 7 th grade so google it bruh lol

5 0

3 years ago

What is the abbreviated electron configuration of cobalt?

drek231 [11]

It's Co just look at the periodic table

7 0

3 years ago

Read 2 more answers

A 100. ml portion of 0.250 m calcium nitrate solution is mixed with 400. ml of 0.100 m nitric acid solution. what is the final c

pshichka [43]

<span>Answer: Moles Ca(NO3)2 = 100 x 0.250 / 1000 = 0.025 Ca(NO3)2 >> Ca2+ + 2NO3- Moles NO3- = 2 x 0.025 = 0.05 Moles HNO3 = 400 x 0.100 / 1000 = 0.04 Total moles = 0.05 + 0.04 = 0.09 Total volume = 500 ml = 0.500 L M = 0.09 / 0.500 = 0.18</span>

6 0

3 years ago

PLEASE HELP I DONT WANT TO FAIL!! ):

Fudgin [204]

Hope this helps :) I didn’t know how to write subscripts so I wrote it down on some paper.