A ball is thrown straight upward and rises to a maximum height of 18.0 m
above its launch point. at what height above its launch point has the
speed of the ball decreased to one-half of its initial value?
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kinematic equation
v^2=u^2-2as; v0=,s=18,a=-10m/s/s
u=root 360
(u/2)^2=u^2-2as
=>s=13.5m
Boron I think look at the periodic table
The fastest in speed of sound is steel. The slowest in speed of sound is oxygen. Hope this helped! I don't really know how to answer this but by looking at the table it looks like this can be one of the conclusions.
Answer:
2.19 N/m
Explanation:
A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:
T = 2π√(m/K)
Where T is the period, m is the mass (in kg), and K is the damping constant. So:
2.4 = 2π√(0.320/K)
√(0.320/K) = 2.4/2π
√(0.320/K) = 0.38197
(√(0.320/K))² = (0.38197)²
0.320/K = 0.1459
K = 2.19 N/m