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xenn [34]
2 years ago
9

What is the net force on this object A: 0 newtons b: 200 newtons c:400 newtons D:600 newtons

Physics
1 answer:
Ilya [14]2 years ago
8 0

Answer:

100kg

Explanation:

Total force =400N+600N=1000N

As we have,

F=m×g

1000N=m×10m/s²

1000N÷10m/s²=m

m=100kg

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Assuming the bar has no weight where does the fulcrum (the top point of the tringle) need to be positioned for the two sides to
Inessa05 [86]

Fulcrum need to be positioned balanced with weight on both the sides following law of lever.

What is the physical law of the lever?

  • It is the foundation for issues with weight and balance. According to this rule, a lever is balanced when the weight multiplied by the arm on one side of the fulcrum, which serves as the pivot point for the device, equals the weight multiplied by the arm on the opposing side.
  • The lever is balanced, in other words, when the sum of the moments about the fulcrum is zero.
  • The situation in which the positive moments (those attempting to turn the lever clockwise) equal the negative moments is known as this (those that try to rotate it counterclockwise).
  • Moving the weights closer to or away from the fulcrum, as well as raising or lowering the weights, can alter the balance point, or CG, of the lever.

Learn more about the Fulcrum with the help of the given link:

brainly.com/question/16422662

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3 0
1 year ago
A table exerts a 4.0 Newton force on a book which lies at rest on its top. The force exerted by the book on the table is
SOVA2 [1]
I believe the correct answer from the choices listed above is the third option. <span>The force exerted by the book on the table is equal to the force exerted by the table which is 4.0 N. The book does not move so it must be that the forces are balanced. Hope this answers the question.</span>
4 0
3 years ago
Read 2 more answers
Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca
OverLord2011 [107]

Answer:

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

8 0
3 years ago
2. Categorize each statement as true or false. A cylindrical capacitor is essentially a parallel-plate capacitor rolled into a t
Kruka [31]

Answer:

Explanation:

False --> A cylindrical capacitor is essentially a parallel plate capacitor rolled into a tube. This is because a cylindrical capacitor comprises two cylinders.

False --> The dielectric constant indicates the distance by which the two plates of a capacitor are separated.

True --> The charge on a capacitor increases quickly at first, then much more slowly as the capacitor charges. This is because the charge on the capacitor increases exponentially.

False --> The voltage across a capacitor in an RC circuit increases linearly during charging. This is because the voltage increases exponentially.

True --> One of the principal purposes of a capacitor is to store electric potential energy.

True --> A capacitor charges rapidly when connected to an RC circuit with a battery. This is because a cylindrical capacitor is basically a parallel plate capacitor rolled into a tube.

6 0
3 years ago
Heather and Jerry are standing on a bridge 49 mm above a river. Heather throws a rock straight down with a speed of 17 m/sm/s .
lara [203]

Answer:

3.467 s

Explanation:

given,

distance , d = 49 mm = 0.049 m

initial speed of the of the rock, v = 17 m/s

time taken by the Heather rock to reach water

using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = -17 t -\dfrac{1}{2}\times 9.8\times t^2

4.9 t² + 17 t - 0.049 = 0

now,

t_1 = \dfrac{-(17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

t₁ = -3.47 s , 0.0028 s

rejecting negative values

t₁ = 0.0028 s

now, time taken by the ball of Jerry

using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = 17 t -\dfrac{1}{2}\times 9.8\times t^2

4.9 t² - 17 t - 0.049 = 0

now,

t_2 = \dfrac{-(-17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

t₂ = 3.47 s ,-0.0028 s

rejecting negative values

t₂ = 3.47 s

now, time elapsed is = t₂ - t₁ = 3.47 - 0.0028 = 3.467 s

5 0
3 years ago
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